Explanation Formula used: The area of a rectangle with the dimensions of length and breadth is, Area=length × breadth The roots of the quadratic equation a x 2 + b x + c = 0 is given by, x = − b ± b 2 − 4 a c 2 a Calculation: Consider the width of the walkway be x . The pool is 50 meters by 25 meters, thus the area of the pool is, A P = 50 × 25 sq meters =1250 sq meters Now, As x is the width of the walkway, then the length of the walkway is 50 + 2 x and width of the walkway is 25 + 2 x . Further, Area of the whole place including the pool and the concretesurface is, A = ( 50 + 2 x ) × ( 25 + 2 x ) Finally, Only 76 square meters of material available to build the nonslip concrete surface, hence, the area of the walkway is given by, A = A W + A P ( 50 + 2 x ) × ( 25 + 2 x ) = 76 + 1250 50.25 + 50.2 x + 2 x .25 + 2 x

8th Edition

ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

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Chapter 8, Problem 47RP

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To calculate: The width of the walkway that will be formed around the outside of the pool which is 50 meters by 25 meters and the amount of material available to make concrete surface is 76 square meters.

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Chapter 8, Problem 46RP

Chapter 8, Problem 48RP

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Chapter 8 Solutions

Intermediate Algebra (8th Edition)

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The width of the walkway that will be formed around the outside of the pool which is 50 meters by 25 meters and the amount of material available to make concrete surface is 76 square meters.

Solution Summary: The author calculates the width of the walkway around the pool, which is 50 meters by 25 meters, and the amount of material available to build the nonslip concrete surface.

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To calculate: The width of the walkway that will be formed around the outside of the pool which is 50 meters by 25 meters and the amount of material available to make concrete surface is 76 square meters.

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Chapter 8 Solutions