The uniform thin rod in Figure P8.47 has mass M = 3.50 kg and length L = 1.00 m and is free to rotate on a friction less pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of (a) the rod’s angular acceleration , (b) the tangential acceleration of the rod’s center of mass, and (c) the tangential acceleration of the rod’s free end. Figure P8.47 Problems 47 and 86.
The uniform thin rod in Figure P8.47 has mass M = 3.50 kg and length L = 1.00 m and is free to rotate on a friction less pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of (a) the rod’s angular acceleration , (b) the tangential acceleration of the rod’s center of mass, and (c) the tangential acceleration of the rod’s free end. Figure P8.47 Problems 47 and 86.
Solution Summary: The author calculates the rod's angular acceleration by rearranging the expression.
The uniform thin rod in Figure P8.47 has mass M = 3.50 kg and length L = 1.00 m and is free to rotate on a friction less pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of (a) the rod’s angular acceleration, (b) the tangential acceleration of the rod’s center of mass, and (c) the tangential acceleration of the rod’s free end.
Figure P8.47 Problems 47 and 86.
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
Consider the circuit shown in the figure. The battery has emf ε = 69 volts and negligible internal resistance. The inductance is L = 0.4 H and the resistances are R 1 = 12 Ω and R 2 = 9.0 Ω. Initially the switch S is open and no currents flow. Then the switch is closed. After leaving the switch closed for a very long time, it is opened again. Just after it is opened, what is the current in R 1?
A capacitor with a capacitance of C = 5.95×10−5 F is charged by connecting it to a 12.5 −V battery. The capacitor is then disconnected from the battery and connected across an inductor with an inductance of L = 1.55 H . At the time 2.35×10−2 s after the connection to the inductor is made, what is the current in the inductor? At that time, how much electrical energy is stored in the inductor?
Can someone help me with this question. Thanks.
Chapter 8 Solutions
Bundle: College Physics, Loose-Leaf Version, 11th + WebAssign Printed Access Card for Serway/Vuille's College Physics, 11th Edition, Multi-Term
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