Explanation Given: The area of a triangle is 70 square centimeters. Its altitude is 6 meters longer than twice the length of the base. Formula used: The area of triangle, Area = 1 2 ( base ) ( height ) . Calculation: Let the altitude of the triangle is h . The base of the triangle is b . From the given data, the altitude of the triangle altitude is 6 meters longer than twice the length of the base. That means, h = 2 b + 6 The area of triangle, Area = 1 2 b h Substitute all the given values in the above equation, 70 = 1 2 b ( 2 b + 6 ) 70 = b 2 + 3 b b 2 + 3 b − 70 = 0 Solve the above equation, b 2 + 10 b − 7 b

MyLab Math with Pearson eText -- 24 MonthStandalone Access Card -- for Intermediate Algebra with Integrated Review

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ISBN: 9780135910023

Author: Tobey, John, Slater, Jeffrey, Blair, Jamie , Crawford, Jenny

Publisher: PEARSON

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Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

Chapter 8, Problem 42RP

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To calculate: The lengths of the altitude and the base of a triangle whose area is 70 square centimeters.

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Chapter 8, Problem 41RP

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The lengths of the altitude and the base of a triangle whose area is 70 square centimeters .

Solution Summary: The author calculates the lengths of the altitude and the base of a triangle whose area is 70square centimeters.

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To calculate: The lengths of the altitude and the base of a triangle whose area is 70 square centimeters.

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