Chapter 8, Problem 37RE

Hooke's Law for an elastic spring states that the distance a spring stretches varies directly as the force applied. If a force of 100 newtons stretches a spring 5 cm, how much will a force of 360 newtons stretch the same spring? Distance of Stretch = [?] cm Hel

The mass center G of the 1305-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. -1264 mm-863 mm Answers: Normal force under each of the front tires: N₁= N Normal force under each of the rear tires: N₁ = N i i

A force of 20 lb is required to hold a spring stretched 2 in. beyond its natural length. How much work W is done in stretching it from its natural length to 8 in. beyond its natural length? W = ft-lb %3D Need Help? Read It Watch It Master It