Path To College Mathematics
1st Edition
ISBN: 9780134654409
Author: Martin-Gay, K. Elayn, 1955-
Publisher: Pearson,
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Chapter 8, Problem 27R
To determine
The percent of scores lies between 70 and 80.
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A cable television company estimates that with x thousand subscribers, its monthly revenue and cost (in thousands of dollars) are given by the following equations.
R(x) = 45x - 0.24x2 C(x) = 257 + 13x
Compare the interest earned from #1 (where simple interest was used) to #5 (where compound interest was used). The principal, annual interest rate, and time were all the same; the only difference was that for #5, interest was compounded quarterly. Does the difference in interest earned make sense? Select one of the following statements. a. No, because more money should have been earned through simple interest than compound interest. b. Yes, because more money was earned through simple interest. For simple interest you earn interest on interest, not just on the amount of principal. c. No, because more money was earned through simple interest. For simple interest you earn interest on interest, not just on the amount of principal. d. Yes, because more money was earned when compounded quarterly. For compound interest you earn interest on interest, not just on the amount of principal.
Reduce the matrix
to reduced row-echelon form.
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A = 3 -2 0 5
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2 1 -2 -14
17
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0
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Chapter 8 Solutions
Path To College Mathematics
Ch. 8.1 - Prob. 1ESCh. 8.1 - Prob. 2ESCh. 8.1 - For each set of numbers, find the mean, median,...Ch. 8.1 - Prob. 4ESCh. 8.1 - Prob. 5ESCh. 8.1 - Prob. 6ESCh. 8.1 - Prob. 7ESCh. 8.1 - For each set of numbers, find the mean, median,...Ch. 8.1 - Prob. 9ESCh. 8.1 - Prob. 10ES
Ch. 8.1 - Prob. 11ESCh. 8.1 - Prob. 12ESCh. 8.1 - Prob. 13ESCh. 8.1 - The ten tallest buildings in the world, completed...Ch. 8.1 - Prob. 15ESCh. 8.1 - Prob. 16ESCh. 8.1 - Prob. 17ESCh. 8.1 - Prob. 18ESCh. 8.1 - Prob. 19ESCh. 8.1 - During an experiment, the following times (in...Ch. 8.1 - Prob. 21ESCh. 8.1 - Prob. 22ESCh. 8.1 - Prob. 23ESCh. 8.1 - Prob. 24ESCh. 8.1 - Prob. 25ESCh. 8.1 - Prob. 26ESCh. 8.1 - Prob. 27ESCh. 8.1 - Prob. 28ESCh. 8.1 - Prob. 29ESCh. 8.1 - Prob. 30ESCh. 8.1 - Below are lengths for the six longest rivers in...Ch. 8.1 - Prob. 32ESCh. 8.1 - Prob. 33ESCh. 8.1 - Prob. 34ESCh. 8.1 - Prob. 35ESCh. 8.1 - Prob. 36ESCh. 8.1 - Prob. 37ESCh. 8.1 - Prob. 38ESCh. 8.1 - Prob. 39ESCh. 8.1 - Prob. 40ESCh. 8.1 - Prob. 41ESCh. 8.1 - Prob. 42ESCh. 8.1 - Prob. 43ESCh. 8.1 - Prob. 44ESCh. 8.1 - Prob. 45ESCh. 8.1 - Prob. 46ESCh. 8.1 - Prob. 47ESCh. 8.1 - Prob. 48ESCh. 8.1 - Prob. 49ESCh. 8.1 - Prob. 50ESCh. 8.1 - Prob. 51ESCh. 8.1 - Prob. 52ESCh. 8.1 - Prob. 53ESCh. 8.1 - Prob. 54ESCh. 8.1 - Prob. 55ESCh. 8.1 - Prob. 56ESCh. 8.1 - Prob. 57ESCh. 8.1 - Prob. 58ESCh. 8.1 - Prob. 59ESCh. 8.1 - Prob. 60ESCh. 8.1 - Prob. 61ESCh. 8.1 - Prob. 62ESCh. 8.2 - Prob. 1ESCh. 8.2 - Prob. 2ESCh. 8.2 - Find the range for each data set. See Example 1....Ch. 8.2 - Prob. 4ESCh. 8.2 - Prob. 5ESCh. 8.2 - Prob. 6ESCh. 8.2 - Prob. 7ESCh. 8.2 - Prob. 8ESCh. 8.2 - Prob. 9ESCh. 8.2 - Prob. 10ESCh. 8.2 - Prob. 11ESCh. 8.2 - Prob. 12ESCh. 8.2 - Prob. 13ESCh. 8.2 - Prob. 14ESCh. 8.2 - Prob. 15ESCh. 8.2 - Prob. 16ESCh. 8.2 - Prob. 17ESCh. 8.2 - Prob. 18ESCh. 8.2 - Prob. 19ESCh. 8.2 - Prob. 20ESCh. 8.2 - Prob. 21ESCh. 8.2 - Prob. 22ESCh. 8.2 - Prob. 23ESCh. 8.2 - Prob. 24ESCh. 8.2 - Prob. 25ESCh. 8.2 - Prob. 26ESCh. 8.2 - Prob. 27ESCh. 8.2 - Prob. 28ESCh. 8.2 - Prob. 29ESCh. 8.2 - Prob. 30ESCh. 8.2 - Prob. 31ESCh. 8.2 - Prob. 32ESCh. 8.2 - Prob. 33ESCh. 8.2 - Prob. 34ESCh. 8.2 - Prob. 35ESCh. 8.2 - Prob. 36ESCh. 8.2 - Prob. 37ESCh. 8.2 - Prob. 38ESCh. 8.2 - Prob. 39ESCh. 8.2 - Prob. 40ESCh. 8.2 - Prob. 41ESCh. 8.2 - Prob. 42ESCh. 8.3 - Prob. 1ESCh. 8.3 - Prob. 2ESCh. 8.3 - Prob. 3ESCh. 8.3 - Prob. 4ESCh. 8.3 - Prob. 5ESCh. 8.3 - Prob. 6ESCh. 8.3 - Prob. 7ESCh. 8.3 - Prob. 8ESCh. 8.3 - Prob. 9ESCh. 8.3 - Prob. 10ESCh. 8.3 - Prob. 11ESCh. 8.3 - Prob. 12ESCh. 8.3 - Prob. 13ESCh. 8.3 - Prob. 14ESCh. 8.3 - Prob. 15ESCh. 8.3 - Prob. 16ESCh. 8.3 - Prob. 17ESCh. 8.3 - Prob. 18ESCh. 8.3 - Prob. 19ESCh. 8.3 - Prob. 20ESCh. 8.3 - Prob. 21ESCh. 8.3 - Prob. 22ESCh. 8.3 - Prob. 23ESCh. 8.3 - Prob. 24ESCh. 8.3 - Prob. 25ESCh. 8.3 - Prob. 26ESCh. 8.3 - Prob. 27ESCh. 8.3 - Prob. 28ESCh. 8.3 - Prob. 29ESCh. 8.3 - Prob. 30ESCh. 8.3 - Prob. 31ESCh. 8.3 - Prob. 32ESCh. 8.3 - Prob. 33ESCh. 8.3 - Prob. 34ESCh. 8.3 - Prob. 35ESCh. 8.3 - Prob. 36ESCh. 8.3 - Prob. 37ESCh. 8.3 - Prob. 38ESCh. 8.3 - Prob. 39ESCh. 8.3 - Prob. 40ESCh. 8.3 - Prob. 41ESCh. 8.3 - Prob. 42ESCh. 8.3 - Prob. 43ESCh. 8.3 - Prob. 44ESCh. 8.3 - Prob. 45ESCh. 8.3 - Prob. 46ESCh. 8.3 - Prob. 47ESCh. 8.3 - Prob. 48ESCh. 8.3 - Prob. 49ESCh. 8.3 - Prob. 50ESCh. 8.3 - Prob. 51ESCh. 8.3 - Prob. 52ESCh. 8.3 - Prob. 53ESCh. 8.3 - Prob. 54ESCh. 8.3 - Prob. 55ESCh. 8.3 - Prob. 56ESCh. 8.3 - Prob. 57ESCh. 8.3 - Prob. 58ESCh. 8.3 - Prob. 59ESCh. 8.3 - Prob. 60ESCh. 8.3 - Prob. 61ESCh. 8.3 - Prob. 62ESCh. 8.3 - Prob. 63ESCh. 8.3 - Prob. 64ESCh. 8.3 - Prob. 65ESCh. 8.3 - Prob. 66ESCh. 8.3 - Prob. 67ESCh. 8.3 - Prob. 68ESCh. 8.3 - Prob. 69ESCh. 8.3 - Prob. 70ESCh. 8.3 - Prob. 71ESCh. 8.3 - Prob. 72ESCh. 8.3 - Prob. 73ESCh. 8.3 - Prob. 74ESCh. 8.3 - Prob. 75ESCh. 8.3 - Prob. 76ESCh. 8.3 - Prob. 77ESCh. 8.3 - Prob. 78ESCh. 8.3 - Prob. 79ESCh. 8 - Prob. 1VCCh. 8 - Prob. 2VCCh. 8 - Prob. 3VCCh. 8 - Prob. 4VCCh. 8 - Prob. 5VCCh. 8 - Prob. 6VCCh. 8 - Prob. 7VCCh. 8 - Prob. 8VCCh. 8 - Prob. 9VCCh. 8 - Prob. 10VCCh. 8 - Prob. 11VCCh. 8 - Prob. 12VCCh. 8 - Prob. 13VCCh. 8 - Prob. 14VCCh. 8 - Prob. 15VCCh. 8 - Prob. 16VCCh. 8 - Prob. 1RCh. 8 - Prob. 2RCh. 8 - Prob. 3RCh. 8 - Prob. 4RCh. 8 - Prob. 5RCh. 8 - Prob. 6RCh. 8 - Prob. 7RCh. 8 - Prob. 8RCh. 8 - Prob. 9RCh. 8 - Prob. 10RCh. 8 - Prob. 11RCh. 8 - Prob. 12RCh. 8 - Prob. 13RCh. 8 - Prob. 14RCh. 8 - Prob. 15RCh. 8 - Prob. 16RCh. 8 - Prob. 17RCh. 8 - Prob. 18RCh. 8 - Prob. 19RCh. 8 - Prob. 20RCh. 8 - Prob. 21RCh. 8 - Prob. 22RCh. 8 - Prob. 23RCh. 8 - Prob. 24RCh. 8 - Prob. 25RCh. 8 - Prob. 26RCh. 8 - Prob. 27RCh. 8 - Prob. 28RCh. 8 - Prob. 29RCh. 8 - Prob. 30RCh. 8 - Prob. 31RCh. 8 - Prob. 32RCh. 8 - Prob. 33RCh. 8 - Prob. 34RCh. 8 - Prob. 35RCh. 8 - Prob. 36RCh. 8 - Prob. 37RCh. 8 - Prob. 38RCh. 8 - Prob. 39RCh. 8 - Prob. 40RCh. 8 - Prob. 41RCh. 8 - Prob. 42RCh. 8 - Prob. 43RCh. 8 - Prob. 44RCh. 8 - Prob. 1GRFTCh. 8 - Prob. 2GRFTCh. 8 - Prob. 3GRFTCh. 8 - Prob. 4GRFTCh. 8 - Prob. 5GRFTCh. 8 - Prob. 6GRFTCh. 8 - Prob. 7GRFTCh. 8 - Prob. 8GRFTCh. 8 - Prob. 9GRFTCh. 8 - Prob. 10GRFTCh. 8 - Prob. 11GRFTCh. 8 - Prob. 12GRFTCh. 8 - Prob. 1TCh. 8 - Prob. 2TCh. 8 - Prob. 3TCh. 8 - Prob. 4TCh. 8 - Prob. 5TCh. 8 - Prob. 6TCh. 8 - Prob. 7TCh. 8 - Prob. 8TCh. 8 - Prob. 9TCh. 8 - Prob. 10TCh. 8 - Prob. 11TCh. 8 - Prob. 12TCh. 8 - Prob. 13TCh. 8 - Prob. 14TCh. 8 - Prob. 15TCh. 8 - Prob. 16TCh. 8 - Prob. 17TCh. 8 - Prob. 18TCh. 8 - Prob. 19TCh. 8 - Prob. 1CRCh. 8 - Prob. 2CRCh. 8 - Prob. 3CRCh. 8 - Prob. 4CRCh. 8 - Prob. 5CRCh. 8 - Prob. 6CRCh. 8 - Prob. 7CRCh. 8 - Prob. 8CRCh. 8 - Prob. 9CRCh. 8 - Prob. 10CRCh. 8 - Prob. 11CRCh. 8 - Prob. 12CRCh. 8 - Prob. 13CRCh. 8 - Prob. 14CRCh. 8 - Prob. 15CRCh. 8 - Prob. 16CRCh. 8 - Prob. 17CRCh. 8 - Prob. 18CRCh. 8 - Prob. 19CRCh. 8 - Prob. 20CRCh. 8 - Solve: (5x1)(2x2+15x+18)=0.Ch. 8 - Prob. 22CRCh. 8 - Prob. 23CRCh. 8 - Prob. 24CRCh. 8 - Prob. 25CRCh. 8 - Prob. 26CRCh. 8 - Prob. 27CRCh. 8 - Prob. 28CRCh. 8 - Prob. 29CRCh. 8 - Prob. 30CRCh. 8 - Prob. 31CRCh. 8 - Prob. 32CRCh. 8 - Prob. 33CRCh. 8 - Prob. 34CRCh. 8 - Prob. 35CRCh. 8 - Prob. 36CRCh. 8 - Prob. 37CRCh. 8 - Prob. 38CRCh. 8 - Prob. 39CRCh. 8 - Prob. 40CRCh. 8 - Prob. 41CRCh. 8 - Prob. 42CRCh. 8 - Prob. 43CRCh. 8 - Prob. 44CR
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- Compare and contrast the simple and compound interest formulas. Which one of the following statements is correct? a. Simple interest and compound interest formulas both yield principal plus interest, so you must subtract the principal to get the amount of interest. b. Simple interest formula yields principal plus interest, so you must subtract the principal to get the amount of interest; Compound interest formula yields only interest, which you must add to the principal to get the final amount. c. Simple interest formula yields only interest, which you must add to the principal to get the final amount; Compound interest formula yields principal plus interest, so you must subtract the principal to get the amount of interest. d. Simple interest and compound interest formulas both yield only interest, which you must add to the principal to get the final amount.arrow_forwardSara would like to go on a vacation in 5 years and she expects her total costs to be $3000. If she invests $2500 into a savings account for those 5 years at 8% interest, compounding semi-annually, how much money will she have? Round your answer to the nearest cent. Show you work. Will she be able to go on vacation? Why or why not?arrow_forwardIf $8000 is deposited into an account earning simple interest at an annual interest rate of 4% for 10 years, howmuch interest was earned? Show you work.arrow_forward
- Why is this proof incorrect? State what statement and/or reason is incorrect and why. Given: Overline OR is congruent to overline OQ, angle N is congruent to angle PProve: Angle 3 is congruent to angle 5 Why is this proof incorrect? Statements Reasons 1. Overline OR is congruent to overline OQ, angle N is congruent to angle P 1. Given 2. Overline ON is congruent to overline OP 2. Converse of the Isosceles Triangle Theorem 3. Triangle ONR is congruent to triangle OPQ 3. SAS 4. Angle 3 is congruent to angle 5 4. CPCTCarrow_forwardx³-343 If k(x) = x-7 complete the table and use the results to find lim k(x). X-7 x 6.9 6.99 6.999 7.001 7.01 7.1 k(x) Complete the table. X 6.9 6.99 6.999 7.001 7.01 7.1 k(x) (Round to three decimal places as needed.)arrow_forward(3) (4 points) Given three vectors a, b, and c, suppose: |bx c = 2 |a|=√√8 • The angle between a and b xc is 0 = 135º. . Calculate the volume a (bxc) of the parallelepiped spanned by the three vectors.arrow_forward
- Calculate these limits. If the limit is ∞ or -∞, write infinity or-infinity. If the limit does not exist, write DNE: Hint: Remember the first thing you check when you are looking at a limit of a quotient is the limit value of the denominator. 1. If the denominator does not go to 0, you should be able to right down the answer immediately. 2. If the denominator goes to 0, but the numerator does not, you will have to check the sign (±) of the quotient, from both sides if the limit is not one-sided. 3. If both the numerator and the denominator go to 0, you have to do the algebraic trick of rationalizing. So, group your limits into these three forms and work with them one group at a time. (a) lim t-pi/2 sint-√ sin 2t+14cos ² t 7 2 2 2cos t (b) lim sint + sin 2t+14cos = ∞ t-pi/2 2 2cos t (c) lim cost-√sin 2t+14cos² t = t-pi/2 2cos t (d) lim t→pi/2 cost+√ sin t + 14cos 2cos ² t = ∞ (e) lim sint-v sin 2 t + 14cos = 0 t-pi/2 (f) lim t-pi/2 sin t +√ sin 2sin 2 t 2 t + 14cos t 2sin t cost- (g)…arrow_forwardThink of this sheet of paper as the plane containing the vectors a = (1,1,0) and b = (2,0,0). Sketch the parallelogram P spanned by a and b. Which diagonal of P represents the vector a--b geometrically?arrow_forwardGiven: AABE ~ ACDE. Prove: AC bisects BD. Note: quadrilateral properties are not permitted in this proof. Step Statement Reason AABE ACDE Given 2 ZDEC ZAEB Vertical angles are congruent try Type of Statement A E B D Carrow_forward
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