Explanation Formula used: The side length ( a ) of the regular hexagon whose distance across the corners ( d ) given is, d = 2 a or a = 0.5 d . The side length ( a ) of the regular hexagon whose distance across the flats ( f ) is given by, f ≈ 1.732 a or a ≈ 0.577 f . The area of the rectangle is A = L W where L is length and W is width. The perimeter of the rectangle is A = 2 ( L + W ) where L is length and W is width. The area of the hexagon is A ≈ 2.598 a 2 where a is side length of the hexagon. Calculation: Note that the area of the shaded region is the difference between the area of rectangle and the hexagon. To find the area of the rectangle find the width of the rectangle. The width of the rectangle is nothing but the distance across the flats of given hexagon. Note that in the given regular hexagon, distance across the corners is 6.4 cm. Find the side length of the regular hexagon as follows. a = 0.5 d = 0.5 × 6.4 cm = 3 .2 cm Therefore, the side length of the hexagon is 3.2 cm. Thus, the distance across the flats of the hexagon is, f ≈ 1.732 a ≈ 1.732 ( 3.2 ) ≈ 5

Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

11th Edition

ISBN: 9780134765785

Author: Hal Saunders

Publisher: PEARSON

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Chapter 8, Problem 21BPS

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The outside perimeter and shaded area of the given figure; round the result to the nearest tenth.

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Chapter 8, Problem 20BPS

Chapter 8, Problem 1CPS

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Chapter 8 Solutions

Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

Ch. 8.1 - What fraction of a circle is this?Ch. 8.1 - Which of these angles measures closest to 45...Ch. 8.1 - A. Solve the following. If you need a protractor,...Ch. 8.1 - Use the geometry relationships to answer the...Ch. 8.1 - Use the geometry relationships to answer the...Ch. 8.1 - In each figure, two parallel lines are cut by a...Ch. 8.1 - Machine Trades A machinist receives a sketch of a...Ch. 8.1 - Carpentry A carpenter wishes to make a...Ch. 8.1 - Carpentry A carpenters square is placed over a...Ch. 8.1 - Carpentry Board 1 must be joined to board 2 at a...

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The outside perimeter and shaded area of the given figure; round the result to the nearest tenth.

Solution Summary: The author calculates the outside perimeter and shaded area of the given figure; round the result to the nearest tenth.

The outside perimeter and shaded area of the given figure; round the result to the nearest tenth.

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Chapter 8 Solutions