Statistics for the Behavioral Sciences
Statistics for the Behavioral Sciences
2nd Edition
ISBN: 9781452286907
Author: Gregory J. Privitera
Publisher: SAGE Publications, Inc
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 8, Problem 20CAP

1

To determine

Identify the decision for each obtained value if α=0.05

  1. a) zobt=2.10
  2. b) zobt=1.70
  3. c) zobt=2.75
  4. d) zobt=3.30

1

Expert Solution
Check Mark

Answer to Problem 20CAP

  1. a) The decision for zobt=2.10 if α=0.05 is rejecting the null hypothesis.
  2. b) The decision for zobt=1.70 if α=0.05 is rejecting the null hypothesis.
  3. c) The decision for zobt=2.75 if α=0.05 is rejecting the null hypothesis.
  4. d) The decision for zobt=3.30 if α=0.05 is retaining the null hypothesis.

Explanation of Solution

Decision Rule:

If the value of the test statistic is greater than the critical value then reject the null hypothesis.

a)

The data gives the value of test statistic value is 2.10, the test is upper-tail test and α=0.05.

From the “Table 8.4”, the critical value corresponding with 0.05 level and upper-tailed test is 1.645.

Justification: The test statistic value is 2.10 and the critical value is 1.645. That is, the test statistic is greater than the critical value. From the decision rule, the null hypothesis is rejected.

Hence, the decision for zobt=2.10 if α=0.05 is rejecting the null hypothesis.

b)

The test statistic value is 1.70 and the critical value is 1.645.

Justification: The test statistic value is greater than the critical value. That is, zobt(=1.70)>critical value(=1.645). From the decision rule, the null hypothesis is rejected.

Hence, the decision for zobt=1.70 if α=0.05 is rejecting the null hypothesis.

c)

The test statistic value is 2.75 and the critical value is 1.645.

Justification: The test statistic value is greater than the critical value. That is, zobt(=2.75)>critical value(=1.645). From the decision rule, the null hypothesis is rejected.

Hence, the decision for zobt=2.75 if α=0.05 is rejecting the null hypothesis.

d)

The test statistic value is –3.30 and the critical value is 1.645.

Justification: The test statistic value is lesser than the critical value. That is, zobt(=3.30)<critical value(=1.645). From the decision rule, the null hypothesis is not rejected.

Hence, the decision for zobt=3.30 if α=0.05 is retaining the null hypothesis.

2

To determine

Identify the decision for each of the obtained value if α=0.01

  1. a) zobt=2.10
  2. b) zobt=1.70
  3. c) zobt=2.75
  4. d) zobt=3.30

2

Expert Solution
Check Mark

Answer to Problem 20CAP

  1. a) The decision for zobt=2.10 if α=0.01 is rejecting the null hypothesis.
  2. b) The decision for zobt=1.70 if α=0.01 is rejecting the null hypothesis.
  3. c) The decision for zobt=2.75 if α=0.01 is rejecting the null hypothesis.
  4. d) The decision for zobt=3.30 if α=0.01 is rejecting the null hypothesis.

Explanation of Solution

Decision Rule:

If the test statistic is greater than the upper critical value or the test statistic is lesser than the lower critical value, then reject the null hypothesis.

a)

The data gives the value of test statistic as 2.10, the test is two-tail test and α=0.01.

From the “Table 8.4”, the critical value corresponding with 0.01 level and two-tailed test is ±2.58.

Justification: The test statistic value is 2.10 and the critical values are –2.58 and 2.58. That is, the test statistic (=2.10) is less than the upper critical value (=2.58) and the test statistic value (=2.10) is greater than lower critical value (=–2.58). From the decision rule, the null hypothesis is not rejected.

Hence, the decision for zobt=2.10 if α=0.01 is retaining the null hypothesis.

b)

The data gives the value of test statistic value is 1.70 and the critical values are –2.58 and 2.58.

Justification: The test statistic (=1.70) is less than the upper critical value (=2.58) and the test statistic value (=1.70) is greater than lower critical value (=–2.58). From the decision rule, the null hypothesis is not rejected.

Hence, the decision for zobt=1.70 if α=0.01 is retaining the null hypothesis.

c)

The test statistic value is 2.75 and the critical values are –2.58 and 2.58.

Justification: The test statistic value (=2.75) is greater than the upper critical value (=2.58). That is, zobt(=2.75)>critical value(=2.58). From the decision rule, the null hypothesis is rejected.

Hence, the decision for zobt=2.75 if α=0.01 is rejecting the null hypothesis.

d)

The test statistic value is –3.30 and the critical values are –2.58 and 2.58.

Justification: The test statistic value (=–3.30) is lesser than the lower critical value (=–2.58). That is, zobt(=3.30)<critical value(=2.58). From the decision rule, the null hypothesis is rejected.

Hence, the decision for zobt=3.30 if α=0.01 is rejecting the null hypothesis.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
T1.4: Let ẞ(G) be the minimum size of a vertex cover, a(G) be the maximum size of an independent set and m(G) = |E(G)|. (i) Prove that if G is triangle free (no induced K3) then m(G) ≤ a(G)B(G). Hints - The neighborhood of a vertex in a triangle free graph must be independent; all edges have at least one end in a vertex cover. (ii) Show that all graphs of order n ≥ 3 and size m> [n2/4] contain a triangle. Hints - you may need to use either elementary calculus or the arithmetic-geometric mean inequality.
We consider the one-period model studied in class as an example. Namely, we assumethat the current stock price is S0 = 10. At time T, the stock has either moved up toSt = 12 (with probability p = 0.6) or down towards St = 8 (with probability 1−p = 0.4).We consider a call option on this stock with maturity T and strike price K = 10. Theinterest rate on the money market is zero.As in class, we assume that you, as a customer, are willing to buy the call option on100 shares of stock for $120. The investor, who sold you the option, can adopt one of thefollowing strategies:ˆ Strategy 1: (seen in class) Buy 50 shares of stock and borrow $380.ˆ Strategy 2: Buy 55 shares of stock and borrow $430.ˆ Strategy 3: Buy 60 shares of stock and borrow $480.ˆ Strategy 4: Buy 40 shares of stock and borrow $280.(a) For each of strategies 2-4, describe the value of the investor’s portfolio at time 0,and at time T for each possible movement of the stock.(b) For each of strategies 2-4, does the investor have…
Negate the following compound statement using De Morgans's laws.
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Bayes' Theorem 1: Introduction and conditional probability; Author: Dr Nic's Maths and Stats;https://www.youtube.com/watch?v=lQVkXfJ-rpU;License: Standard YouTube License, CC-BY
What is Conditional Probability | Bayes Theorem | Conditional Probability Examples & Problems; Author: ACADGILD;https://www.youtube.com/watch?v=MxOny_1y2Q4;License: Standard YouTube License, CC-BY
Bayes' Theorem of Probability With Tree Diagrams & Venn Diagrams; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=OByl4RJxnKA;License: Standard YouTube License, CC-BY
Bayes' Theorem - The Simplest Case; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=XQoLVl31ZfQ;License: Standard Youtube License