Sustainable Energy
Sustainable Energy
2nd Edition
ISBN: 9781337551663
Author: DUNLAP, Richard A.
Publisher: Cengage,
Question
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Chapter 8, Problem 1P
To determine

Find the power radiated by a woodstove.

Expert Solution & Answer
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Answer to Problem 1P

The power radiated by a woodstove is 3.7kW¯.

Given information:

The size of the woodstove is 65cm×55cm×85cm.

The surface temperature (T) is 120°C.

The emissivity ε is 1.

Calculation:

Find the surface area of the woodstove.

A=2×H×D+2×H×B+2×D×B=2×65×55+2×65×85+2×55×85=27,550cm2=2.755m2

Convert the surface temperature from Degree Celsius to Kelvin:

120°C=120°C+273K=393K

Consider the Stephen Boltzmann constant σ is 5.67×108Wm2K4.

Find the surface radiation (P):

P=AεσT4=2.755m2×1×5.67×108Wm2K4×393K4=3,726W3.7kW

Thus, the power radiated by a woodstove is 3.7kW¯.

Explanation of Solution

Given information:

The size of the woodstove is 65cm×55cm×85cm.

The surface temperature (T) is 120°C.

The emissivity ε is 1.

Calculation:

Find the surface area of the woodstove.

A=2×H×D+2×H×B+2×D×B=2×65×55+2×65×85+2×55×85=27,550cm2=2.755m2

Convert the surface temperature from Degree Celsius to Kelvin:

120°C=120°C+273K=393K

Consider the Stephen Boltzmann constant σ is 5.67×108Wm2K4.

Find the surface radiation (P):

P=AεσT4=2.755m2×1×5.67×108Wm2K4×393K4=3,726W3.7kW

Thus, the power radiated by a woodstove is 3.7kW¯.

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