Explanation Given data: Refer to the Figure P8.1 in the textbook for the standing of a student on a very light, rigid board. Mass of the student ( m ) is 64 kg. From the Figure, the distance between the two scales is 2.0 m and the distance between the student and left scale is 1.5 m. Therefore, the distance of the student from the left scale ( d left ) is 1.5 m. The distance between the two scales ( d ) is 2.0 m. Formula used: Write the expression for static equilibrium condition of the torque as follows. ∑ τ = 0 (1) Here, ∑ τ is the sum of the torques acting on any object. Write the expression for weight of the object as follows. w = m g (2) Here, m is the mass of the object, and g is the acceleration due to gravity, which is 9.8 m s 2 . Write the expression for torque in terms of force and distance as follows. τ = F d (3) Here, F is the force, and d is the distance. Explanation: As the board is very light and rigid, consider the board as massless. Therefore, it does not contribute to the scale reading. Calculation of weight of the student: Substitute 64 kg for m , and 9.8 m s 2 for g in equation (2), w = ( 64 kg ) ( 9.8 m s 2 ) = 627.2 kg ⋅ m s 2 ≃ 627 N { ∵ 1 kg ⋅ m s 2 = 1 N } From the given data, it is clear that, the sum of the readings is equal to the weight of the person. Therefore, write the expression for readings of the scale as follows. n left + n right = w (4) Here, n left is the reading on the left scale, n right is the reading on the right scale, and w is the weight of the student. Substitute 627 N for w in equation (4), n left + n right = 627 N (5) Consider the board rests on the left scale and compute the torques around point on the left scale. From the Figure, the weight of the student creates a clockwise (negative) torque and the normal force of the right scale creates a counter clockwise (positive) torque. Therefore, modify the expression in equation (1) as follows. τ right + ( − τ w ) = 0 (6) Here, τ right is the torque created by the normal force of the right scale, and τ w is the torque created by the weight of the student

College Physics: A Strategic Approach (4th Edition)

4th Edition

ISBN: 9780134609034

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

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Chapter 8, Problem 1P

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To find: The reading on each of the scales.

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Chapter 8, Problem 27MCQ

Chapter 8, Problem 2P

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College Physics: A Strategic Approach (4th Edition)

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Ch. 8 - Take a spring and cut it in half to make two...Ch. 8 - A wire is stretched right to its breaking point by...Ch. 8 - Prob. 13CQ Ch. 8 - Prob. 14CQ Ch. 8 - Steel nails are rigid and unbending. Steel wool is...Ch. 8 - Two children hold opposite ends of a lightweight,...Ch. 8 - Prob. 19MCQ Ch. 8 - Prob. 20MCQ Ch. 8 - Prob. 21MCQ Ch. 8 - Prob. 22MCQ Ch. 8 - Prob. 23MCQ Ch. 8 - Prob. 24MCQ Ch. 8 - Prob. 25MCQ Ch. 8 - Prob. 26MCQ Ch. 8 - You have a heavy piece of equipment hanging from a...Ch. 8 - Prob. 1P Ch. 8 - Prob. 2P Ch. 8 - Prob. 3P Ch. 8 - Prob. 4P Ch. 8 - Youre carrying a 3.6-m-long, 25 kg pole to a...Ch. 8 - Prob. 6P Ch. 8 - Prob. 7P Ch. 8 - Prob. 9P Ch. 8 - Prob. 11P Ch. 8 - Prob. 13P Ch. 8 - Prob. 14P Ch. 8 - Prob. 15P Ch. 8 - The stability of a vehicle is often rated by the...Ch. 8 - Prob. 18P Ch. 8 - A car manufacturer claims that you can drive its...Ch. 8 - Prob. 20P Ch. 8 - An orthodontic spring, connected between the upper...Ch. 8 - Prob. 22P Ch. 8 - Experiments using optical tweezers measure the...Ch. 8 - Prob. 24P Ch. 8 - One end of a 10-cm-long spring is attached to the...Ch. 8 - Prob. 26P Ch. 8 - A spring has an unstretched length of 10 cm. It...Ch. 8 - A spring stretches 5.0 cm when a 0.20 kg block is...Ch. 8 - You need to make a spring scale to measure the...Ch. 8 - Prob. 30P Ch. 8 - A force stretches a wire by 1.0 mm. a. A second...Ch. 8 - Prob. 32P Ch. 8 - What hanging mass will stretch a 2.0-m-long,...Ch. 8 - An 80-cm-long, 1.0-mm-diameter steel guitar string...Ch. 8 - A mineshaft has an ore elevator hung from a single...Ch. 8 - The normal force of the ground on the foot can...Ch. 8 - A three-legged wooden bar stool made out of solid...Ch. 8 - Prob. 38P Ch. 8 - Prob. 39P Ch. 8 - Prob. 40P Ch. 8 - A glass optical fiber in a communications system...Ch. 8 - The Achilles tendon connects the muscles in your...Ch. 8 - Prob. 44P Ch. 8 - Prob. 47P Ch. 8 - Prob. 48P Ch. 8 - Prob. 49P Ch. 8 - Prob. 51GP Ch. 8 - Prob. 52GP Ch. 8 - Prob. 53GP Ch. 8 - Prob. 55GP Ch. 8 - Two identical, side-by-side springs with spring...Ch. 8 - Prob. 57GP Ch. 8 - Prob. 58GP Ch. 8 - Prob. 59GP Ch. 8 - A 25 kg child bounces on a pogo stick. The pogo...Ch. 8 - Prob. 61GP Ch. 8 - In the hammer throw, an athlete spins a heavy mass...Ch. 8 - There is a disk of cartilage between each pair of...Ch. 8 - Orb spiders make silk with a typical diameter of...Ch. 8 - Larger animals have sturdier bones than smaller...Ch. 8 - Prob. 67GP Ch. 8 - Prob. 68GP Ch. 8 - Prob. 69MSPP Ch. 8 - Prob. 70MSPP Ch. 8 - Prob. 71MSPP Ch. 8 - Prob. 72MSPP

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