Chapter 8, Problem 1DE

Interpretation Introduction

Interpretation: The name or formula of the given coordination compounds is to be determined.

Concept Introduction: The name of the ligands is written first in the alphabetical order followed by the name and oxidation state of transition metal ion.

(a)

To determine: The name of the given coordination complex $\left[\text{Mo}{\left({\text{NH}}_3\right)}_3{\text{Br}}_3\right]{\text{NO}}_3$ .

Answer to Problem 1DE

Solution:

The name of the given coordination compound is Triamminetribromomolybdenum(IV) nitrate.

Explanation of Solution

The nomenclature of coordination compound is based on the certain rules which are written as,

1. The cation is named first followed by anion.
2. The ligands are named before metal ion in the alphabetical order.
3. The oxidation state of the metal ion is written just after the name of the metal.

The given complex contains three ammonia molecules which are named as triammine and three bromine molecules written as tribromo. Thus, the name of the given coordination compound is Triamminetribromomolybdenum(IV) nitrate.

Conclusion

The name of the given coordination compound is Triamminetribromomolybdenum(IV) nitrate.

(b)

Interpretation Introduction

To determine: The name of the given coordination complex ${\left({\text{NH}}_3\right)}_2\left[{\text{CuBr}}_4\right]$ .

Answer to Problem 1DE

Solution:

The name of the given coordination compound is Ammonium tetrabromocuprate(II).

Explanation of Solution

The nomenclature of coordination compound is based on the certain rules which are written as,

1. The cation is named first followed by anion.
2. The ligands are named before metal ion in the alphabetical order.
3. The oxidation state of the metal ion is written just after the name of the metal.

The given complex contains four bromine molecules written as tetrabromo. Thus, the name of the given coordination compound on the basis of the given rules is Ammonium tetrabromocuprate(II).

Conclusion

The name of the given coordination compound is Ammonium tetrabromocuprate(II).

(c)

Interpretation Introduction

To determine: The formula of the given coordination compound sodium diaquabis(oxalate)ruthenate(III).

Answer to Problem 1DE

Solution: The formula of the given coordination compound is $\text{Na}\left[\text{Ru}{\left({\text{H}}_2\text{O}\right)}_2{\left({\text{C}}_2{\text{O}}_4\right)}_2\right]$ .

Explanation of Solution

The nomenclature of coordination compound is based on the certain rules which are written as,

1. The cation is named first followed by anion.
2. The ligands are named before metal ion in the alphabetical order.
3. The oxidation state of the metal ion is written just after the name of the metal.

The given name has sodium as a cation, it is written first. After that the name of ligands is diaqua means two water molecules and bis oxalate means two oxalate molecules; thereby ruthenate as the transition metal ion. Thus, the formula of the given coordination compound on the basis of the given rules is $\text{Na}\left[\text{Ru}{\left({\text{H}}_2\text{O}\right)}_2{\left({\text{C}}_2{\text{O}}_4\right)}_2\right]$ .

Conclusion

The formula of the given coordination compound is $\text{Na}\left[\text{Ru}{\left({\text{H}}_2\text{O}\right)}_2{\left({\text{C}}_2{\text{O}}_4\right)}_2\right]$ .