Loose Leaf For Integrated Principles Of Zoology
18th Edition
ISBN: 9781260411140
Author: Cleveland P Hickman Jr. Emeritus, Susan L. Keen, David J Eisenhour Professor PhD, Allan Larson, Helen I'Anson Associate Professor of Biology
Publisher: McGraw-Hill Education
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Chapter 8, Problem 18RQ
Name two organ-system derivatives of each of the three germ layers.
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Use the following tree diagram to answer Questions #8-10.
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tree to the left?
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b) Hippo and pig
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9) CIRCLE on the tree diagram where the
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cow is.
10) Put a SQUARE on the tree diagram
where the common ancestor between a pig
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Chapter 8 Solutions
Loose Leaf For Integrated Principles Of Zoology
Ch. 8 - What is meant by epigenesis? How did Kaspar...Ch. 8 - How is an egg (oocyte) prepared during oogenesis...Ch. 8 - Describe events that follow contact of a...Ch. 8 - What is meant by the term activation in...Ch. 8 - How does amount of yolk affect cleavage? Compare...Ch. 8 - What is the difference between radial and spiral...Ch. 8 - What other developmental hallmarks are often...Ch. 8 - What is indirect development?Ch. 8 - Using sea star embryos as an example, describe...Ch. 8 - What is the difference between schizocoelous and...
Ch. 8 - Describe two different experimental approaches...Ch. 8 - What is meant by induction in embryology? Describe...Ch. 8 - What are homeotic genes and what is the homeobox...Ch. 8 - What is the embryological evidence that...Ch. 8 - What are the four extraembryonic membranes of...Ch. 8 - What is the fate of the four extraembryonic...Ch. 8 - Explain what the growth cone that Ross Harrison...Ch. 8 - Name two organ-system derivatives of each of the...Ch. 8 - Prob. 19RQCh. 8 - SCNT makes possible therapeutic cloning. What are...
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- Explain down bellow what happens to the cell: Decreased pH in mitochondria Increased ATP Decreased pH in cytosol Increased hydrolysis Decreasing glycogen and triglycerides Increased MAP kinase activity Poor ion transport → For each one:→ What normally happens?→ What is wrong now?→ How does it mess up the cell?arrow_forwardAn 1100 pound equine patient was given 20 mg/kg sucralfate 3 times a day, 2.8 mg/kg famotidine twice a day, and 10mg/kg doxycycline twice a day. Sucralfate comes as a 1 gm tablet, famotidine as 20 mg tablets, and doxycycline as 100mg tablets. All are in bottles of 100 tablets.How many total mg are needed for the patient and how many tablets of each would be needed to provide each dose?How many bottles of each would be needed to have available if this patient were to be on this drug regimen for 5 days?arrow_forwardThe patient needs a solution of 2.5% dextrose in Lactated Ringer’s solution to run at 75 ml/hr for at least the next 12hours. LRS comes in fluid bags of 500 ml, 1 Liter, 3 Liters and 5 Liters. How can a 2.5% solution be made by adding50% dextrose to the LRS?arrow_forward
- “Gretchen” was a 68-pound canine who came to the VMTH as small animal surgery patient. She receivedacepromazine, 0.2 mg/kg from a 10 mg/ml solution and oxymorphone, 0.08 mg/kg from a 1 mg/ml solution before surgery.What are the mechanisms of action of acepromazine and oxymorphone? Why would they be given together?How many mg provide each dose and how many ml of each of these solutions were given?arrow_forwardAfter surgery, “Gretchen” was put on carprofen, 1 mg/pound bid (twice a day). The tablets come in 25, 75 and 100 mgsizes. Which size tablet would be appropriate?What is the mechanism of action of carprofen?An outpatient prescription was written for her so she would have enough for 10 days. How many tablets did she need?What information needs to be on her out-patient prescription?arrow_forwardJoden Koepp olor in chickens is due to incomplete dominance. BB = Black chicken, WW = White BLOOD TYPES Arhite chicken is In humans, Rh positive blood is dominant (R) over Rh negative blood (r). A man with type 0, Rh positive blood (whose mother had Rh negative blood), marries a woman with type AB, Rh negative blood. Several children were born. is? R R Genotypes Phenotypes RRR RR Rr Rr 4/16 RR R RR RK Rr Rr 4/16 rr 3/4 Rh posi 1/4 Rh negu 1/2 Rr rr rr rrrr 88 888 75 e genotype of the man? the genotype of the woman? The mother of the man had type AB blood.arrow_forward
- Please indentify the unknown organismarrow_forward5G JA ATTC 3 3 CTIA A1G5 5 GAAT I I3 3 CTIA AA5 Fig. 5-3: The Eco restriction site (left) would be cleaved at the locations indicated by the arrows. However, a SNP in the position shown in gray (right) would prevent cleavage at this site by EcoRI One of the SNPs in B. rapa is found within the Park14 locus and can be detected by RFLP analysis. The CT polymorphism is found in the intron of the Bra013780 gene found on Chromosome 1. The Park14 allele with the "C" in the SNP has two EcoRI sites and thus is cleaved twice by EcoRI If there is a "T" in that SNP, one of the EcoRI sites is altered, so the Park14 allele with the T in the SNP has only one EcoRI site (Fig. 5-3). Park14 allele with SNP(C) Park14 allele with SNPT) 839 EcoRI 1101 EcoRI 839 EcoRI Fig. 5.4: Schematic restriction maps of the two different Park14 alleles (1316 bp long) of B. rapa. Where on these maps is the CT SNP located? 90 The primers used to amplify the DNA at the Park14 locus (see Fig. 5 and Table 3 of Slankster et…arrow_forwardFrom your previous experiment, you found that this enhancer activates stripe 2 of eve expression. When you sequence this enhancer you find several binding sites for the gap gene, Giant. To test how Giant interacts with eve, you decide to remove all of the Giant binding sites from the eve enhancer. What results do you expect to see with respect to eve expression?arrow_forward
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