Explanation Given Information: Two dice are rolled, one of the dice is red and other is green and the game is losing if both the dice give same number and if the green dice give odd number and red one gives even number. All other combination are winning ones. Formula used: The principle of complementary events, P ( A ′ ) = 1 − P ( A ) According to the formula for probability, the probability of event E , which has n ( E ) possible outcomes out of n ( S ) total outcomes is, P ( E ) = n ( E ) n ( S ) Calculation: Consider the event that the winning combination is rolled to be E . Thus, the sample space of rolling two dice is, { ( 1 , 1 ) ( 1 , 2 ) ( 1 , 3 ) ( 1 , 4 ) ( 1 , 5 ) ( 1 , 6 ) ( 2 , 1 ) ( 2 , 2 ) ( 2 , 3 ) ( 2 , 4 ) ( 2 , 5 ) ( 2 , 6 ) ( 3 , 1 ) ( 3 , 2 ) ( 3 , 3 ) ( 3 , 4 ) ( 3 , 5 ) ( 3 , 6 ) ( 4 , 1 ) ( 4 , 2 ) ( 4 , 3 ) ( 4 , 4 ) ( 4 , 5 ) ( 4 , 6 ) ( 5 , 1 ) ( 5 , 2 ) ( 5 , 3 ) <

Student Solutions Manual for Waner/Costenoble's Finite Math and Applied Calculus, 7th

7th Edition

ISBN: 9781337275972

Author: Waner, Stefan; Costenoble, Steven

Publisher: Cengage Learning

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Chapter 8, Problem 12RE

To determine

To calculate: The probability that you roll a winning combination on the two dice if one of the dice is red and other is green and the game is losing if both the dice give same number and if the green dice give odd number and red one gives even number.

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Chapter 8, Problem 11RE

Chapter 8, Problem 13RE

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Chapter 8 Solutions

Student Solutions Manual for Waner/Costenoble's Finite Math and Applied Calculus, 7th

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