Physics
Physics
3rd Edition
ISBN: 9781259233616
Author: GIAMBATTISTA
Publisher: MCG
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 8, Problem 129P

(a)

To determine

The magnitude of static frictional force exerted by road on each tire.

(a)

Expert Solution
Check Mark

Answer to Problem 129P

The magnitude of static frictional force exerted by road on each tire is froad=62Nbackwards_.

Explanation of Solution

Consider Newton’s second law to find the force exerted by road on bicycle, since it is the only external force acting on bicycle.

Write the Mathematical expression for Newton’s second law

Fx=Max (I)

Here, Fx is the force, M is the mass, and ax is the acceleration

Both wheels of bicycle experience external force between road and wheel. Hence the expression for that force in terms of velocity is

2froad=MΔvxΔt=M(vfvi)Δt (II)

Here, Δt is the change in time, vf is the final velocity, and vi is the initial velocity

Therefore, the expression of frictional force is

froad=M(vfvi)2Δt (III)

Conclusion:

Substitute, 74kg for M, 0m/s for vi, 75m/s for vf, and 4.5s for Δt in equation (III)

froad=74kg(07.5m/s)2(4.5s)=61.7N62N,backwards

Therefore, the magnitude of static frictional force exerted by road on each tire is froad=62Nbackwards_.

(b)

To determine

The angular acceleration of two wheels.

(b)

Expert Solution
Check Mark

Answer to Problem 129P

The angular acceleration of two wheels is α=4.8rad/s2_.

Explanation of Solution

Write the expression for angular speed

ω=vr (IV)

Here, ω is the angular speed, v is the linear velocity, r is the radius

Write the expression for angular acceleration

α=ωfωiΔt (V)

Here, α is the angular acceleration, Δt is the change in time, ωf is the final angular speed, ωi is the initial angular speed

Conclusion:

Substitute, 7.5m/s for v, 0.35m for r in equation (VI)

ω=7.5m/s0.35m=21.4rad/s

Substitute 0 for ωi, 21.4rad/s for ωf, 4.5s for Δt in equation (V)

α=021.4rad/s4.5s=4.75rad/s24.8rad/s2

Therefore, the angular acceleration of two wheels is α=4.8rad/s2_, opposite to the direction of original rotation.

(c)

To determine

The net torque acting on wheel.

(c)

Expert Solution
Check Mark

Answer to Problem 129P

The net torque acting on wheel is τ=0.76Nm_.

Explanation of Solution

Write the expression for net torque

τ=Iα (VI)

Here, τ is the torque, I is the moment of inertia, α is the angular acceleration

Write the expression for moment of inertia

I=mr2 (VII)

Here, m is the mass, r is the radius

Substitute equation (VII) in (VI)

τ=mr2α (VIII)

Conclusion:

Substitute, 1.3kg for m, 0.35m for r, 4.76rad/s2 for α in equation (VIII)

τ=(1.3kg)(0.35m)2(4.76rad/s2)=0.758Nm0.76Nmopposite to the direction of original rotation

Therefore, the net torque acting on wheel is τ=0.76Nm_, opposite to the direction of original rotation.

(d)

To determine

The normal force applied to a wheel by each of the brake pads.

(d)

Expert Solution
Check Mark

Answer to Problem 129P

The normal force applied to a wheel by each of the brake pads is fbrake=35N_.

Explanation of Solution

There are two components of net torque acting on each wheel, one is static friction force acting between road and wheel, and the other is the kinetic friction force acting on brake pads.

The direction of both forces will be opposite to each other. If the bicycle turns to right, static friction force will be in clockwise direction, and kinetic friction will be in counter clockwise direction.

Write the expression for net force in terms components

τ=froadr+2fbraker (IX)

Rearrange equation (IX) to obtain expression for fbrake

fbrake=τ+froadr2r (X)

Write the expression for normal force

N=fbrakeμ (XI)

Conclusion:

Substitute, 0.758Nm for τ, 0.35m for r, and 61.7N for  in equation (X)

fbrake=0.758Nm+(61.7N)(0.35m)2(0.35m)=31.9N

Substitute 0.9 for μ, 31.9N for fbrake in equation (XI)

N=31.9N0.9=35N

Therefore, the normal force applied to a wheel by each of the brake pads is fbrake=35N_.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
suggest a reason ultrasound cleaning is better than cleaning by hand?
Checkpoint 4 The figure shows four orientations of an electric di- pole in an external electric field. Rank the orienta- tions according to (a) the magnitude of the torque on the dipole and (b) the potential energy of the di- pole, greatest first. (1) (2) E (4)
What is integrated science. What is fractional distillation What is simple distillation

Chapter 8 Solutions

Physics

Ch. 8.4 - Prob. 8.8PPCh. 8.4 - Prob. 8.9PPCh. 8.6 - Prob. 8.11PPCh. 8.7 - Prob. 8.12PPCh. 8.7 - Prob. 8.7CPCh. 8.7 - Prob. 8.13PPCh. 8.8 - Prob. 8.8CPCh. 8.8 - Prob. 8.14PPCh. 8.8 - Prob. 8.15PPCh. 8 - Prob. 1CQCh. 8 - Prob. 2CQCh. 8 - Prob. 3CQCh. 8 - Prob. 4CQCh. 8 - Prob. 5CQCh. 8 - Prob. 6CQCh. 8 - Prob. 7CQCh. 8 - Prob. 8CQCh. 8 - Prob. 9CQCh. 8 - Prob. 10CQCh. 8 - Prob. 11CQCh. 8 - Prob. 12CQCh. 8 - Prob. 13CQCh. 8 - Prob. 14CQCh. 8 - Prob. 15CQCh. 8 - Prob. 16CQCh. 8 - Prob. 17CQCh. 8 - Prob. 18CQCh. 8 - Prob. 19CQCh. 8 - Prob. 20CQCh. 8 - Prob. 21CQCh. 8 - Prob. 1MCQCh. 8 - Prob. 2MCQCh. 8 - Prob. 3MCQCh. 8 - Prob. 4MCQCh. 8 - Prob. 5MCQCh. 8 - Prob. 6MCQCh. 8 - Prob. 7MCQCh. 8 - Prob. 9MCQCh. 8 - Prob. 10MCQCh. 8 - Prob. 1PCh. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - Prob. 7PCh. 8 - Prob. 8PCh. 8 - Prob. 9PCh. 8 - Prob. 10PCh. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - 13. The pull cord of a lawnmower engine is wound...Ch. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - 32. A sculpture is 4.00 m tall and has its center...Ch. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - 42. A man is doing push-ups. He has a mass of 68...Ch. 8 - Prob. 43PCh. 8 - Prob. 44PCh. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - Prob. 48PCh. 8 - Prob. 49PCh. 8 - Prob. 50PCh. 8 - Prob. 51PCh. 8 - Prob. 52PCh. 8 - Prob. 53PCh. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - Prob. 56PCh. 8 - Prob. 57PCh. 8 - Prob. 58PCh. 8 - Prob. 59PCh. 8 - Prob. 60PCh. 8 - Prob. 61PCh. 8 - Prob. 62PCh. 8 - Prob. 63PCh. 8 - Prob. 64PCh. 8 - Prob. 65PCh. 8 - Prob. 66PCh. 8 - Prob. 67PCh. 8 - Prob. 68PCh. 8 - Prob. 69PCh. 8 - Prob. 70PCh. 8 - Prob. 71PCh. 8 - Prob. 72PCh. 8 - Prob. 73PCh. 8 - Prob. 74PCh. 8 - Prob. 75PCh. 8 - Prob. 76PCh. 8 - Prob. 77PCh. 8 - Prob. 78PCh. 8 - Prob. 79PCh. 8 - Prob. 80PCh. 8 - Prob. 81PCh. 8 - Prob. 82PCh. 8 - Prob. 83PCh. 8 - Prob. 84PCh. 8 - Problems 85 and 86. A solid cylindrical disk is to...Ch. 8 - Prob. 86PCh. 8 - Prob. 87PCh. 8 - Prob. 88PCh. 8 - Prob. 89PCh. 8 - Prob. 90PCh. 8 - Prob. 91PCh. 8 - Prob. 92PCh. 8 - Prob. 93PCh. 8 - Prob. 94PCh. 8 - Prob. 95PCh. 8 - Prob. 96PCh. 8 - Prob. 97PCh. 8 - Prob. 98PCh. 8 - Prob. 99PCh. 8 - Prob. 100PCh. 8 - Prob. 101PCh. 8 - Prob. 102PCh. 8 - Prob. 103PCh. 8 - Prob. 104PCh. 8 - Prob. 105PCh. 8 - Prob. 106PCh. 8 - Prob. 107PCh. 8 - Prob. 108PCh. 8 - Prob. 109PCh. 8 - Prob. 110PCh. 8 - Prob. 111PCh. 8 - Prob. 112PCh. 8 - Prob. 113PCh. 8 - Prob. 114PCh. 8 - Prob. 115PCh. 8 - 116. A large clock has a second hand with a mass...Ch. 8 - 117. A planet moves around the Sun in an...Ch. 8 - 118. A 68 kg woman stands straight with both feet...Ch. 8 - Prob. 119PCh. 8 - Prob. 120PCh. 8 - Prob. 121PCh. 8 - Prob. 122PCh. 8 - Prob. 123PCh. 8 - Prob. 124PCh. 8 - Prob. 125PCh. 8 - Prob. 126PCh. 8 - Prob. 127PCh. 8 - Prob. 128PCh. 8 - Prob. 129PCh. 8 - Prob. 130PCh. 8 - Prob. 131PCh. 8 - Prob. 132PCh. 8 - Prob. 133P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
What is Torque? | Physics | Extraclass.com; Author: Extraclass Official;https://www.youtube.com/watch?v=zXxrAJld9mo;License: Standard YouTube License, CC-BY