EBK INTRODUCTORY CHEMISTRY
EBK INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 9780100480483
Author: DECOSTE
Publisher: YUZU
Question
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Chapter 8, Problem 111AP
Interpretation Introduction

(a)

Interpretation:

The molar mass of adipic acid (C6H10O4) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculate by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of adipic acid (C6H10O4) is 146.1 g/mol.

Explanation of Solution

Molar mass of adipic acid (C6H10O4)

=[6(Atomic mass of C)+10(Atomic mass of H)+4(Atomic mass of O)]=[6(12.01)+10(1.008)+4(15.99)]g/mol=146.1 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
  • Atomic mass of oxygen = 15.99 g/mol.
Interpretation Introduction

(b)

Interpretation:

The molar mass of caffeine (C8H10N4O2) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculate by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of caffeine (C8H10N4O2) is 194.1 g/mol.

Explanation of Solution

Molar mass of caffeine (C8H10N4O2)

=[8(atomic mass of C)+10(atomic mass of H)+4(atomic mass of N)+2(atomic mass of O)]=[8(12.01)+10(1.008)+4(14)+2(15.99)]g/mol=194.1 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
  • Atomic mass of nitrogen = 14 g/mol.
  • Atomic mass of oxygen = 15.99 g/mol.
Interpretation Introduction

(c)

Interpretation:

The molar mass of eicosane (C20H42) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculate by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of eicosane (C20H42) is 282.5 g/mol.

Explanation of Solution

Molar mass of eicosane (C20H42)

=[20(atomic mass of C)+42(atomic mass of H)]=[20(12.01)+42(1.008)]g/mol=282.5 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
Interpretation Introduction

(d)

Interpretation:

The molar mass of cyclohexanol (C6H11OH) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculate by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of cyclohexanol (C6H11OH) is 100.15 g/mol.

Explanation of Solution

Molar mass of cyclohexanol (C6H11OH)

=[6(Atomic mass of C)+12(Atomic mass of H)+1(Atomic mass of O)]=[6(12.01)+12(1.008)+1(15.99)]g/mol=100.15 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
  • Atomic mass of oxygen = 15.99 g/mol.
Interpretation Introduction

(e)

Interpretation:

The molar mass of vinyl acetate (C4H6O2) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculate by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of vinyl acetate (C4H6O2) is 86.09 g/mol.

Explanation of Solution

Molar mass of vinyl acetate (C4H6O2)

=[4(Atomic mass of C)+6(Atomic mass of H)+2(Atomic mass of O)]=[4(12.01)+6(1.008)+2(15.99)] g/mol=86.09 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
  • Atomic mass of oxygen = 15.99 g/mol.
Interpretation Introduction

(f)

Interpretation:

The molar mass of dextrose (C6H12O6) should be calculated.

Concept Introduction:

Molar mass refers to the mass of one mole of the compound. It is calculated by adding the mass of each atom of each element present in one molecule of a compound.

Expert Solution
Check Mark

Answer to Problem 111AP

The molar mass of dextrose (C6H12O6) is 180.1 g/mol.

Explanation of Solution

Molar mass of dextrose (C6H12O6)

=[6(Atomic mass of C)+12(Atomic mass of H)+6(Atomic mass of O)]=[6(12.01)+12(1.008)+6(15.99)] g/mol =180.1 g/mol

Here,

  • Atomic mass of carbon = 12.01 g/mol.
  • Atomic mass of hydrogen = 1.008 g/mol.
  • Atomic mass of oxygen = 15.99 g/mol.

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Chapter 8 Solutions

EBK INTRODUCTORY CHEMISTRY

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