(a) Interpretation: The stronger nucleophile out of Br − and Cl − in a polar protic solvent is to be identified. Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

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Answer 1

Question

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

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Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0

Answer 2

Question

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

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Answer 3

Question

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

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Answer 4

Question

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

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Answer 5

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Answer 6

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Answer 7

Chapter 7.8, Problem 15P

Interpretation Introduction

(a)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Answer 8

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Answer 9

Interpretation Introduction

(b)

Interpretation: The stronger nucleophile out of Br− and Cl− in a polar aprotic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. However, in polar aprotic solvent, O−H bond or N−H is absent.

Answer 10

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Answer 11

Interpretation Introduction

(c)

Interpretation: The stronger nucleophile out of HS− and F− in a polar protic solvent is to be identified.

Concept introduction: Solvent is required to dissolve the starting material in it. The substitution reaction involves polar starting reactant which is soluble in polar solvent. A solvent in which hydrogen atom is bonded to electronegative O or N atom is termed as polar protic solvent. The nucleophilicity of anion that has small size is higher than the anion that has larger size.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 7.1 - Problem 7.1 Telfairine, a naturally occurring...Ch. 7.2 - Give the IUPAC name for each compound. a. b. c. d.Ch. 7.2 - Prob. 3P Ch. 7.3 - An sp3 hybridized CCl bond is more polar than an...Ch. 7.4 - Prob. 5P Ch. 7.6 - Prob. 6P Ch. 7.7 - Prob. 10P Ch. 7.8 - Prob. 15P Ch. 7.8 - Prob. 16P Ch. 7.8 - Prob. 17P

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