(a) Explanation The T − v diagram with initial and final condition of the water is shown below. Figure-(1) Write the expression for the exergy at the initial state. E 1 = m [ ( u 1 − u 0 ) + p 0 ( v 1 − v 0 ) − T 0 ( s 1 − s 0 ) + V 1 2 2000 + g z 1 1000 ] (I) Here, the mass of the water is m , the specific internal energy at the point 1 of the water is u 1 , the specific internal energy of the dead state is u 0 , the atmospheric pressure is p 0 , the specific volume at the point is v 1 , the specific volume at the dead state is v 0 , the specific entropy at the point 1 is s 1 , the specific entropy at the dead state is s 0 , the velocity of the water at point 1 is V 1 , the acceleration due to gravity is g and the elevation at the state 1is z 1 . Conclusion: Substitute 1 kg for m , 298 K for T 0 , 25 m / s for V 1 , 9.81 m / s 2 for g , 5 m for z 1 100 kPa for p 0 , 1.673 m 3 / kg for v 1 , 0.00010029 m 3 / kg for v 0 , 7.3549 kJ / kg ⋅ K for s 1 , 0.3674 kJ / kg ⋅ K for s 0 , 2506 (b) To determine The exergy at the final state. (c) To determine The change in exergy.

8th Edition

ISBN: 2818440116926

Author: MORAN

Publisher: WILEY CONS

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Chapter 7.7, Problem 23P

(a)

To determine

The exergy at the initial state.

(b)

To determine

The exergy at the final state.

(c)

To determine

The change in exergy.

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Chapter 7.7, Problem 22P

Chapter 7.7, Problem 24P

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FUNDAMENTALS OF ENGINEERING THERMODYNAM

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