Area of an Octagon (a) The area A of a regular octagon is given by the formula A = 8 r 2 tan π 8 , where r is the apothem, which is a line segment from the center of the octagon perpendicular to a side. See the figure. Find the exact area of a regular octagon whose apothem is 12 inches. (b) The area A of a regular octagon is also given by the formula A = 2 a 2 cot π 8 , where a is the length of a side. Find the exact area of a regular octagon whose side is 9 centimeters.
Area of an Octagon (a) The area A of a regular octagon is given by the formula A = 8 r 2 tan π 8 , where r is the apothem, which is a line segment from the center of the octagon perpendicular to a side. See the figure. Find the exact area of a regular octagon whose apothem is 12 inches. (b) The area A of a regular octagon is also given by the formula A = 2 a 2 cot π 8 , where a is the length of a side. Find the exact area of a regular octagon whose side is 9 centimeters.
Solution Summary: The author calculates the exact area of the regular octagon with apothem 12 inches.
(a) The area
A
of a regular octagon is given by the formula
A
=
8
r
2
tan
π
8
,
where
r
is the apothem, which is a line segment from the center of the octagon perpendicular to a side. See the figure. Find the exact area of a regular octagon whose apothem is 12 inches.
(b) The area
A
of a regular octagon is also given by the formula
A
=
2
a
2
cot
π
8
, where
a
is the length of a side. Find the exact area of a regular octagon whose side is 9 centimeters.
Use Euler's method to numerically integrate
dy
dx
-2x+12x² - 20x +8.5
from x=0 to x=4 with a step size of 0.5. The initial condition at x=0 is y=1. Recall
that the exact solution is given by y = -0.5x+4x³- 10x² + 8.5x+1
Find an equation of the line tangent to the graph of f(x) = (5x-9)(x+4) at (2,6).
Find the point on the graph of the given function at which the slope of the tangent line is the given slope.
2
f(x)=8x²+4x-7; slope of the tangent line = -3
Chapter 7 Solutions
Mylab Math With Pearson Etext -- Standalone Access Card -- For Precalculus (11th Edition)
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