Cantor’s cuts. Start with the unit interval [0, 1]. Remove the middle third of that interval and you will have [0, 1/3] and (2/3, 1]. Next, remove the middle third of each of those intervals. You will have [0, 1/9], [2/9, 1/3], [2/3, 7/9], and [8/9, 1] remaining. If you repeat the process of removing the middle third forever, the points that remain constitute the Cantor Set. Describe infinitely many points that remain in the Cantor Set.
Cantor’s cuts. Start with the unit interval [0, 1]. Remove the middle third of that interval and you will have [0, 1/3] and (2/3, 1]. Next, remove the middle third of each of those intervals. You will have [0, 1/9], [2/9, 1/3], [2/3, 7/9], and [8/9, 1] remaining. If you repeat the process of removing the middle third forever, the points that remain constitute the Cantor Set. Describe infinitely many points that remain in the Cantor Set.
Cantor’s cuts. Start with the unit interval [0, 1]. Remove the middle third of that interval and you will have [0, 1/3] and (2/3, 1]. Next, remove the middle third of each of those intervals. You will have [0, 1/9], [2/9, 1/3], [2/3, 7/9], and [8/9, 1] remaining. If you repeat the process of removing the middle third forever, the points that remain constitute the Cantor Set. Describe infinitely many points that remain in the Cantor Set.
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