Chapter 7.5, Problem 18P

Write each expression in radical form.

${(99r)}^{\frac{1}{2}}$

To determine

To write the expression ${\left(99r\right)}^{\frac{1}{2}}$ in radical form.

Answer to Problem 18P

  ${\left(99r\right)}^{\frac{1}{2}}=\sqrt[2]{99r}=\sqrt{99r}$

Explanation of Solution

Given information :

Given expression $36t^{\frac{1}{4}}$

Since $a^{\frac{1}{n}}=\sqrt[n]{a}\mathrm{............}(i)$

Now consider ${\left(99r\right)}^{\frac{1}{2}}=\sqrt[2]{99r}\text{from}\text{rule}(i)$

Hence, ${\left(99r\right)}^{\frac{1}{2}}=\sqrt[2]{99r}=\sqrt{99r}$