Explanation Result used: The vertex and the y -intercept of the quadratic function y = a x 2 + b x + c is ( − b 2 a , f ( − b 2 a ) ) and ( 0 , c ) . Description: Compare the equation y = − 2 x 2 − 5 x with the general quadratic equation . y = a ↓ x 2 + b ↓ x + c ↓ y = − 2 x 2 − 5 x + 0 From the above, the value of a , b and c are observed to be −2, −5 and 0, respectively. Compute the vertex as follows. Obtain the value of x -coordinate in ( − b 2 a , f ( − b 2 a ) ) . Substitute a = − 2 and b = − 5 in − b 2 a . − b 2 a = − ( − 5 ) 2 ( − 2 ) = 5 − 4 = − 5 4 Thus, the x -coordinate of the vertex is − 5 4 . Substitute x = − 5 4 in y = − 2 x 2 − 5 x and obtain the value of y -coordinate

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ISBN: 9780134508290

Author: Evans

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Chapter 7.4, Problem 8E

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To sketch: The graph of the function y=−2x2−5x using the vertex and the y-intercept.

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Chapter 7.4, Problem 7E

Chapter 7.4, Problem 9E

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Chapter 7 Solutions

EBK BASIC TECHNICAL MATHEMATICS

Ch. 7.1 - Solve for x: x2 + 4x − 21 = 0 Ch. 7.1 - Prob. 2PE Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E

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The graph of the function y = − 2 x 2 − 5 x using the vertex and the y -intercept.

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Chapter 7 Solutions