The properties in Problem 83 provide us with another way to write the equation of a line parallel or perpendicular to a given line that contains a given point not on the line. For example, suppose that we want the equation of the line perpendicular to 3x + 4y = 6 that contains the point (1, 2). The form 4x - 3y = k, where k is a constant, represents a family of lines perpendicular to 3x + 4y = 6 because we have satisfied the condition AA' = -BB'. Therefore, to find what specific line of the family contains (1, 2), we substitute 1 for x and 2 for y to determine k.4x - 3y = k4(1) - 3(2) = k-2 = k Thus the equation of the desired line is 4x - 3y = -2. Use the properties from Problem 83 to help write the equation of each of the following lines.(a) Contains (1, 8) and is parallel to 2x + 3y = 6(b) Contains (-1, 4) and is parallel to x - 2y = 4(c) Contains (2, -7) and is perpendicular to 3x - 5y = 10(d) Contains (-1, -4) and is perpendicular to 2x + 5y = 12
The properties in Problem 83 provide us with another way to write the equation of a line parallel or perpendicular to a given line that contains a given point not on the line. For example, suppose that we want the equation of the line perpendicular to 3x + 4y = 6 that contains the point (1, 2). The form 4x - 3y = k, where k is a constant, represents a family of lines perpendicular to 3x + 4y = 6 because we have satisfied the condition AA' = -BB'. Therefore, to find what specific line of the family contains (1, 2), we substitute 1 for x and 2 for y to determine k.
4x - 3y = k
4(1) - 3(2) = k
-2 = k Thus the equation of the desired line is 4x - 3y = -2. Use the properties from Problem 83 to help write the equation of each of the following lines.
(a) Contains (1, 8) and is parallel to 2x + 3y = 6
(b) Contains (-1, 4) and is parallel to x - 2y = 4
(c) Contains (2, -7) and is perpendicular to 3x - 5y = 10
(d) Contains (-1, -4) and is perpendicular to 2x + 5y = 12
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