(a) Explanation Calculation: It is given that n = 15 , x ¯ = 37.3 , and s = 13.9 . Confidence interval: Software Procedure: Step-by-step procedure to obtain the 95% confidence interval for the true mean adrenocorticotropic level of sleepers one hour prior to waking using the MINITAB software: Choose Stat > Basic Statistics > 1-Sample t . In Summarized data, enter the sample size as 15 and mean as 37.3 . In Standard deviation , enter a value for s as 13 (b) To determine Interpret the interval in Part(a). (c) To determine Write the inference about the mean adrenocorticotropic level of sleepers under two conditions.

13th Edition

ISBN: 9780135820100

Author: MCCLAVE, James T., Sincich, Terry

Publisher: PEARSON

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Question

Chapter 7.3, Problem 51ACA

(a)

To determine

Construct the 95% confidence interval for the true mean adrenocorticotropic level of sleepers one hour prior to waking.

(b)

To determine

Interpret the interval in Part(a).

(c)

To determine

Write the inference about the mean adrenocorticotropic level of sleepers under two conditions.

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Chapter 7.3, Problem 50ACI

Chapter 7.4, Problem 52UP

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To evaluate the success of a 1-year experimental program designed to increase the mathematical achievement of underprivileged high school seniors, a random sample of participants in the program will be selected and their mathematics scores will be compared with the previous year’s statewide average of 525 for underprivileged seniors. The researchers want to determine whether the experimental program has increased the mean achievement level over the previous year’s statewide average. If alpha=.05, what sample size is needed to have a probability of Type II error of at most .025 if the actual mean is increased to 550? From previous results, sigma=80.

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