For Exercises 35–44, an equation of a parabola ( x − h ) 2 = 4 p ( y − k ) or ( y − k ) 2 = 4 p ( x − h ) is given. a. Identify the vertex, value of p , focus, and focal diameter of the parabola. b. Identify the endpoints of the latus rectum. c. Graph the parabola. d. Write equations for the directrix and axis of symmetry. (See Example 4) 2 ( y − 3 ) = 1 10 ( x + 6 ) 2
For Exercises 35–44, an equation of a parabola ( x − h ) 2 = 4 p ( y − k ) or ( y − k ) 2 = 4 p ( x − h ) is given. a. Identify the vertex, value of p , focus, and focal diameter of the parabola. b. Identify the endpoints of the latus rectum. c. Graph the parabola. d. Write equations for the directrix and axis of symmetry. (See Example 4) 2 ( y − 3 ) = 1 10 ( x + 6 ) 2
Solution Summary: The author calculates the vertex, value of p, focus and focal diameter of the parabola.
For Exercises 27–34, an equation of a parabola x = 4py or y = 4px is given.
a. Identify the vertex, value of p, focus, and focal diameter of the parabola.
b. Identify the endpoints of the latus rectum.
c. Graph the parabola.
d. Write equations for the directrix and axis of symmetry. (See Examples 2-3)
27. x
-4y
28. x
-20y
29. 10y
= 80x
30. 3y = 12x
31. 4x
40y
32. 2x
14y
33. y =
34. y = -2x
= -X
%3D
For Exercises 43–48, the equation represents a conic section (nondegenerative case).
a. Identify the type of conic section. (See Example 6)
b. Graph the equation on a graphing utility.
43. 4x – 4xy + 5y – 20 = 0
44. 6x + 4V3xy + 2y - 18x + 18V3y – 72 = 0
45. 2x – 6xy + 3y²
- 4x + 12y – 9 = 0
46. 5x – 3xy + 2y – 6 = 0
47. 4x + 8xy + 4y – 2x – 5y – 2 = 0
48. 4x? + 8V3xy + 3y + 2x – 12y – 6 = 0
For Exercises 67–70, identify the equation as representing an ellipse or a hyperbola, and match the equation with the graph.
(x – 5)²
67.
(y + 2)²
= 1
(x – 5)?
68.
(y + 2)?
= 1
49
36
36
49
(x - 5)?
69.
(y + 2)²
= 1
(y + 2)²
= 1
(x - 5)?
49
36
70.
49
36
А.
В.
С.
D.
15
12
41
6
-6-4-2
4 6 8 10 12 14
4 6 8 10 12 14
-6 -4
2.
4 6 8 10l 12 14
-6
1k 15 18 21
-6
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