In Exercises 21-26, use a polar coordinate system like the one shown for Exercises 1-10 to plot each point with the given polar coordinates. Then find another representation ( r , θ ) of this point in which a. r > 0 , 2 π < θ < 4 π . b. r < 0 , 0 < θ < 2 π . c. r > 0 , − 2 π < θ < 0. ( 4 , π 2 )
In Exercises 21-26, use a polar coordinate system like the one shown for Exercises 1-10 to plot each point with the given polar coordinates. Then find another representation ( r , θ ) of this point in which a. r > 0 , 2 π < θ < 4 π . b. r < 0 , 0 < θ < 2 π . c. r > 0 , − 2 π < θ < 0. ( 4 , π 2 )
Solution Summary: The author illustrates how the point is (4,pi2) in polar coordinate system.
In Exercises 21-26, use a polar coordinate system like the one shown for Exercises 1-10 to plot each point with the given polar coordinates. Then find another representation
(
r
,
θ
)
of this point in which
a.
r
>
0
,
2
π
<
θ
<
4
π
.
b.
r
<
0
,
0
<
θ
<
2
π
.
c.
r
>
0
,
−
2
π
<
θ
<
0.
(
4
,
π
2
)
System that uses coordinates to uniquely determine the position of points. The most common coordinate system is the Cartesian system, where points are given by distance along a horizontal x-axis and vertical y-axis from the origin. A polar coordinate system locates a point by its direction relative to a reference direction and its distance from a given point. In three dimensions, it leads to cylindrical and spherical coordinates.
a)
[1√2-31x+1√3-11y = x (1 - √2) + √34
LI√2-21x-1√3-3/4= √34 -
√2x-4
Please Help me answer this linear algebra question. This is a practice textbook question.
1. a scientist observed a bacterium in a microscope. it measured about .0000029 meter in diameter which of the following is closest to it? A- 2 x 10^-6, B- 2 x 10^-5, C- 3 x 10^-5, or D- 3 x 10^-6
2.express the product of 500 and 400 in scientific notation. is it 2 x 10^5 or 2 x 10^4 or 2 x 10^3 or 20 x 10^4
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Polar Coordinates Basic Introduction, Conversion to Rectangular, How to Plot Points, Negative R Valu; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=aSdaT62ndYE;License: Standard YouTube License, CC-BY