To prove: If z = r ( cos θ + i sin θ ) is a non-zero complex number in trigonometric form, then z − 1 = r − 1 ( cos ( − θ ) + i sin ( − θ ) ) .

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Answer 1

Question

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

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Answer 2

Question

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

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Answer 3

Question

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

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Answer 4

Question

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

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Answer 5

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

Answer 6

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

Answer 7

Chapter 7.3, Problem 24E

To determine

To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

Answer 8

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Answer 9

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Answer 10

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Answer 11

To prove: If z = r ( cos θ + i sin θ ) is a non-zero complex number in trigonometric form, then z − 1 = r − 1 ( cos ( − θ ) + i sin ( − θ ) ) .

Solution Summary: The author explains how z=rleft is a non-zero complex number in trigonometric form. The notation stackrel z indicates the conjugate of

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To prove: If z=r(cos θ + i sin θ) is a non-zero complex number in trigonometric form, then z−1=r−1(cos (− θ) + i sin (− θ)).

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Chapter 7 Solutions