Explanation Given: The equation of the hyperbola, ( y − 1 ) 2 4 − ( x + 2 ) 2 = 1 . Formula used: The coordinate of the focus of the hyperbola ( y − k ) 2 b 2 − ( x − h ) 2 a 2 = 1 is ( h , k ± c ) , where c 2 = a 2 + b 2 . The equation of the asymptotes is y = ± b a x + ( k ∓ b h a ) . Graph: Sketch the hyperbola ( y − 1 ) 2 4 − ( x + 2 ) 2 = 1 and the asymptotes y = 2 x + 5 , y = − 2 x − 3 in the same window using TI83 calculator Consider: ( y − 1 ) 2 4 − ( x + 2 ) 2 = 1 y = 1 ± 2 ( x + 2 ) 2 + 1 Step 1: Press the [Y=]key, then there will appear the equations for y . Step 2: Enter the equations in Y 1 . Here, Y 1 = 1 + 2 ( ( X + 2 ) 2 + 1 ) . Step 3: Enter the equations in Y 2 . Here, Y 2 = 1 − 2 ( ( X + 2 ) 2 + 1 ) . Step 4: Enter the equations in Y 3 . Here, Y 3 = 2 X + 5 . Step 5: Enter the equations in Y 4 . Here, Y 4 = − 2 X − 3

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ISBN: 9780321916600

Author: Mark Dugopolski

Publisher: PEARSON

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Chapter 7.3, Problem 23E

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To graph: The hyperbola (y−1)24−(x+2)2=1 and calculate the foci and the equations of the asymptotes.

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Chapter 7.3, Problem 22E

Chapter 7.3, Problem 24E

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Chapter 7 Solutions

College Algebra (6th Edition)

Ch. 7.1 - True or False? Explain. A parabola with focus (0,...Ch. 7.1 - Prob. 2FT Ch. 7.1 - Prob. 3FT Ch. 7.1 - Prob. 4FT Ch. 7.1 - Prob. 5FT Ch. 7.1 - Prob. 6FT Ch. 7.1 - Prob. 7FT Ch. 7.1 - Prob. 8FT Ch. 7.1 - Prob. 9FT Ch. 7.1 - Prob. 10FT

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To graph: The hyperbola ( y − 1 ) 2 4 − ( x + 2 ) 2 = 1 and calculate the foci and the equations of the asymptotes.

Solution Summary: The author explains how to graph the hyperbola and the asymptotes using the TI83 calculator.

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To graph: The hyperbola (y−1)24−(x+2)2=1 and calculate the foci and the equations of the asymptotes.

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Chapter 7 Solutions