Chapter 7.1, Problem 59PS

Now let’s use a graphing calculator to get a graph of $\text{C}=\frac{5}{9}\left(\text{F}-32\right)$. By letting $\text{F}=x$ and $\text{C}=y$, we obtain Figure $7.15$. Pay special attention to the boundaries on $x$. These values were chosen so that the fraction

$\frac{\left(\text{Maximum}\text{value}\text{of}\text{x}\right)\text{minus}\left(\text{Minimum}\text{value}\text{of}\text{x}\right)}{95}$

Would be equal to $1$. The viewing window of the graphing calculator used to produce Figure $7.15$ is $95$ pixels (dots) wide. Therefore, we use $95$ as the denominator of the fraction. We chose the boundaries for $y$ to make sure that the cursor would be visible on the screen when we looked for certain values.

(This was accomplished by setting the aforementioned fraction equal to 1 ) By moving the cursor to each of the $\text{F}$ values, we can complete the table as follows.

$\text{F}$	$-5$	$5$	$9$	$11$	$12$	$20$	$30$	$45$	$60$
$\text{C}$	$-21$	$-15$	$-13$	$-12$	$-11$	$-7$	$-1$	$7$	$16$

The $\text{C}$ values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation $\text{C}=\frac{5}{9}\left(\text{F}-32\right)$.