Chapter 7.1, Problem 1GP

Solution

To state: The first six terms of the sequence $a_n=n+4$ .

The resultant terms are $a_1=5,a_2=6,a_3=7,a_4=8,a_5=9,a_6=10$ .

Given information:

The given sequence is $a_n=n+4$ .

Explanation:

A sequence is a function whose domain is a set of consecutive integers. If a domain is not specified, it is understood that domain starts with 1.

Now consider the given sequence,

  $a_n=n+4$

Now substitute 1 for n for the first term and simplify,

  $\begin{array}{c}{a}_1=1+4\\ =5\end{array}$

Now substitute 2 for n for the first term and simplify,

  $\begin{array}{c}{a}_2=2+4\\ =6\end{array}$

Similarly, find the remaining 4 terms,

  $\begin{array}{c}{a}_3=3+4\\ =7\\ a_4=4+4\\ =8\\ a_5=5+4\\ =9\\ a_6=6+4\\ =10\end{array}$

Therefore, the first six terms are $a_1=5,a_2=6,a_3=7,a_4=8,a_5=9,a_6=10$ .