Interpretation Introduction To determine: The dissociated amount. Explanation Given: Power of light P = 885 mW . Time t = 10 .0 min . λ = 280 nm ϕ = 0.24 Explanation: Power is the energy emitted per unit time. Convert the units of power as follows: 885 mW × ( 1 W 1000 mW ) × ( 1 Js − 1 1 W ) = 0 .885 Js − 1 Calculate the energy absorbed in ten minutes as follows: E ( absorbed ) = ( 0 .885 Js − 1 ) × 10 .0 min × ( 60 s 1 .0 min ) = 531 .0 J The energy of one photon is related to the wavelength as follows: E ( 1 photon ) = h c λ Here, E ( 1 photon ) is the energy of one photon, h is the Planck’s constant, λ is the wavelength, and c is the speed of light. Calculate the energy of one photon by substituting the values as follows: E ( 1 photon ) = h c λ = ( 6.626 × 10 − 34 J .s ) × ( 3.0 × 10 8 ms − 1 ) 280 nm × ( 1 nm 1 × 10 − 9 m ) = 7

Chemistry: A Molecular Approach, Books a la Carte Edition (4th Edition)

4th Edition

ISBN: 9780134113593

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 7, Problem 93E

Interpretation Introduction

To determine: The dissociated amount.

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Chapter 7, Problem 92E

Chapter 7, Problem 94E

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Chapter 7 Solutions

Chemistry: A Molecular Approach, Books a la Carte Edition (4th Edition)

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