Interpretation Introduction To determine: The percentage of naphthalene molecules which emit a photon. Explanation Given: The volume of ampule ( V ) is 5.00 mL . The molarity of the solution ( M ) is 0.100 M . The total energy emitted by naphthalene ( E ) is 15.5 J . The wavelength of naphthalene ( λ ) is 349 nm Explanation: The molarity of a substance is equal to the mass of solute per liters of a solution. M = n V Here, M is the molarity of solution, n is the number of moles, and V is the volume of solution in liters. One milliliter is equal to 10 − 3 liters. Convert milliliters to liters as follows: 5.00 mL = 5.00 mL × 10 − 3 L 1 mL = 0.005 L Now calculate the number of moles of naphthalene as follows: n = M × V Substitute 0.005 L for V and 0.100 M for M as follows: n = 0.100 M × 0.005 L = 0.100 mol / L × 0.005 L = 0 .0005 mol So, the number of moles of naphthalene is 0 .0005 mol . Now calculate the number of molecules of naphthalene as follows: The number of molecules is equal to the product of the number of moles and Avogadro number. Total number of molelcules = n × N A Total number of molecules = 0 .0005 × 6.023 × 10 23 = 3.011 × 10 20 molecules The energy of the photon emitted by naphthalene is given as follows: E Photon = h c λ The Plank constant ( h ) is 6.626 × 10 − 34 Js . The speed of light ( c ) is 3 × 10 8 m / s

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Chapter 7, Problem 90E

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To determine: The percentage of naphthalene molecules which emit a photon.

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Chapter 7, Problem 89E

Chapter 7, Problem 91E

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Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

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