The probable subshells for the given principal quantum number n = 8 have to be identified. Concept introduction: Principal Quantum Number (n): In an atom, the electron energy mainly depends on principal quantum number. The energy of an electron becomes lower when the value of n is smaller. The orbital size also depends on n. The size of orbital increases with increase in value of principal quantum number (n) Angular Momentum Quantum Number (l): It helps to differentiate different shapes of orbitals for given n. For a given n, there are n different shapes of orbitals are present and are denoted as l. Angular momentum quantum number is also known as Azimuthal quantum number. The possible values of angular momentum quantum number between 0 and (n-1) . If the n is 3 , then l value is 0 , 1 , 2 Subshell Number of orbital in subshell Number of Electrons that can fill subshell s 1 2 p 3 6 d 5 10 f 7 14 g 9 18
The probable subshells for the given principal quantum number n = 8 have to be identified. Concept introduction: Principal Quantum Number (n): In an atom, the electron energy mainly depends on principal quantum number. The energy of an electron becomes lower when the value of n is smaller. The orbital size also depends on n. The size of orbital increases with increase in value of principal quantum number (n) Angular Momentum Quantum Number (l): It helps to differentiate different shapes of orbitals for given n. For a given n, there are n different shapes of orbitals are present and are denoted as l. Angular momentum quantum number is also known as Azimuthal quantum number. The possible values of angular momentum quantum number between 0 and (n-1) . If the n is 3 , then l value is 0 , 1 , 2 Subshell Number of orbital in subshell Number of Electrons that can fill subshell s 1 2 p 3 6 d 5 10 f 7 14 g 9 18
Solution Summary: The author explains the probable subshells for the given principal quantum number.
Definition Definition Product of the moment of inertia and angular velocity of the rotating body: (L) = Iω Angular momentum is a vector quantity, and it has both magnitude and direction. The magnitude of angular momentum is represented by the length of the vector, and the direction is the same as the direction of angular velocity.
Chapter 7, Problem 7.90QP
Interpretation Introduction
Interpretation:
The probable subshells for the given principal quantum number n=8 have to be identified.
Concept introduction:
Principal Quantum Number (n): In an atom, the electron energy mainly depends on principal quantum number. The energy of an electron becomes lower when the value of n is smaller. The orbital size also depends on n. The size of orbital increases with increase in value of principal quantum number (n)
Angular Momentum Quantum Number (l): It helps to differentiate different shapes of orbitals for given n. For a given n, there are n different shapes of orbitals are present and are denoted as l. Angular momentum quantum number is also known as Azimuthal quantum number. The possible values of angular momentum quantum number between 0and(n-1). If the n is 3, then l value is 0,1,2
Using the Nernst equation to calculate nonstandard cell voltage
A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction:
MnO2 (s)+4H* (aq)+2Cr²+ (aq) → Mn²+ (aq)+2H₂O (1)+2Cr³+ (aq)
+
2+
2+
3+
Suppose the cell is prepared with 7.44 M H* and 0.485 M Cr²+ in one half-cell and 7.92 M Mn² and 3.73 M Cr³+ in the other.
Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
☐
x10
μ
Х
5
?
000
日。
Calculating standard reaction free energy from standard reduction...
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG° for the following redox reaction.
Be sure your answer has the correct number of significant digits.
NO (g) +H₂O (1) + Cu²+ (aq) → HNO₂ (aq) +H* (aq)+Cu* (aq)
kJ
-
☐ x10
x10
olo
18
Ar
Calculating the pH of a weak base titrated with a strong acid
b
An analytical chemist is titrating 116.9 mL of a 0.7700M solution of aniline (C6H5NH2) with a 0.5300M solution of HNO3. The pK of aniline is 9.37.
Calculate the pH of the base solution after the chemist has added 184.2 mL of the HNO 3 solution to it.
Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added.
Round your answer to 2 decimal places.
pH = ☐
☑
5
Chapter 7 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
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Quantum Numbers, Atomic Orbitals, and Electron Configurations; Author: Professor Dave Explains;https://www.youtube.com/watch?v=Aoi4j8es4gQ;License: Standard YouTube License, CC-BY