Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
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Chapter 7, Problem 7.7QA
Interpretation Introduction
To find:
Mass of substance
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The electrode balance potential is -0.118 V and the interface potential difference
is +5 mV. The overvoltage n will be 0.005 - (-0.118) = 0.123 V. Is it correct?
In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?
In the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.
Chapter 7 Solutions
Chemistry: An Atoms-Focused Approach (Second Edition)
Ch. 7 - Prob. 7.1VPCh. 7 - Prob. 7.2VPCh. 7 - Prob. 7.3VPCh. 7 - Prob. 7.4VPCh. 7 - Prob. 7.5VPCh. 7 - Prob. 7.6VPCh. 7 - Prob. 7.7QACh. 7 - Prob. 7.8QACh. 7 - Prob. 7.9QACh. 7 - Prob. 7.10QA
Ch. 7 - Prob. 7.11QACh. 7 - Prob. 7.12QACh. 7 - Prob. 7.13QACh. 7 - Prob. 7.14QACh. 7 - Prob. 7.15QACh. 7 - Prob. 7.16QACh. 7 - Prob. 7.17QACh. 7 - Prob. 7.18QACh. 7 - Prob. 7.19QACh. 7 - Prob. 7.20QACh. 7 - Prob. 7.21QACh. 7 - Prob. 7.22QACh. 7 - Prob. 7.23QACh. 7 - Prob. 7.24QACh. 7 - Prob. 7.25QACh. 7 - Prob. 7.26QACh. 7 - Prob. 7.27QACh. 7 - Prob. 7.28QACh. 7 - Prob. 7.29QACh. 7 - Prob. 7.30QACh. 7 - Prob. 7.31QACh. 7 - Prob. 7.32QACh. 7 - Prob. 7.33QACh. 7 - Prob. 7.34QACh. 7 - Prob. 7.35QACh. 7 - Prob. 7.36QACh. 7 - Prob. 7.37QACh. 7 - Prob. 7.38QACh. 7 - Prob. 7.39QACh. 7 - Prob. 7.40QACh. 7 - Prob. 7.41QACh. 7 - Prob. 7.42QACh. 7 - Prob. 7.43QACh. 7 - Prob. 7.44QACh. 7 - Prob. 7.45QACh. 7 - Prob. 7.46QACh. 7 - Prob. 7.47QACh. 7 - Prob. 7.48QACh. 7 - Prob. 7.49QACh. 7 - Prob. 7.50QACh. 7 - Prob. 7.51QACh. 7 - Prob. 7.52QACh. 7 - Prob. 7.53QACh. 7 - Prob. 7.54QACh. 7 - Prob. 7.55QACh. 7 - Prob. 7.56QACh. 7 - Prob. 7.57QACh. 7 - Prob. 7.58QACh. 7 - Prob. 7.59QACh. 7 - Prob. 7.60QACh. 7 - Prob. 7.61QACh. 7 - Prob. 7.62QACh. 7 - Prob. 7.63QACh. 7 - Prob. 7.64QACh. 7 - Prob. 7.65QACh. 7 - Prob. 7.66QACh. 7 - Prob. 7.67QACh. 7 - Prob. 7.68QACh. 7 - Prob. 7.69QACh. 7 - Prob. 7.70QACh. 7 - Prob. 7.71QACh. 7 - Prob. 7.72QACh. 7 - Prob. 7.73QACh. 7 - Prob. 7.74QACh. 7 - Prob. 7.75QACh. 7 - Prob. 7.76QACh. 7 - Prob. 7.77QACh. 7 - Prob. 7.78QACh. 7 - Prob. 7.79QACh. 7 - Prob. 7.80QACh. 7 - Prob. 7.81QACh. 7 - Prob. 7.82QACh. 7 - Prob. 7.83QACh. 7 - Prob. 7.84QACh. 7 - Prob. 7.85QACh. 7 - Prob. 7.86QACh. 7 - Prob. 7.87QACh. 7 - Prob. 7.88QACh. 7 - Prob. 7.89QACh. 7 - Prob. 7.90QACh. 7 - Prob. 7.91QACh. 7 - Prob. 7.92QACh. 7 - Prob. 7.93QACh. 7 - Prob. 7.94QACh. 7 - Prob. 7.95QACh. 7 - Prob. 7.96QACh. 7 - Prob. 7.97QACh. 7 - Prob. 7.98QACh. 7 - Prob. 7.99QACh. 7 - Prob. 7.100QACh. 7 - Prob. 7.101QACh. 7 - Prob. 7.102QACh. 7 - Prob. 7.103QACh. 7 - Prob. 7.104QACh. 7 - Prob. 7.105QACh. 7 - Prob. 7.106QACh. 7 - Prob. 7.107QACh. 7 - Prob. 7.108QACh. 7 - Prob. 7.109QACh. 7 - Prob. 7.110QA
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- In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.arrow_forwardIn a Pt electrode, H2(1 atm) | H+(a=1), the interchange current density of an electrode is 0.79 mA cm-2. ¿Qué corriente flow across the electrode of área 5 cm2 when the difference in potential of the interface is +5 mV?.arrow_forwardIf the current voltage is n = 0.14 V, indicate which of the 2 voltage formulas of the ley of Tafel must be applied i a a) == exp (1-B). xp[(1 - ß³): Fn Fn a b) == exp B RT RTarrow_forward
- If the current voltage is n = 0.14 V. Indicate which of the 2 formulas must be applied a) = a T = i exp[(1 - p) F Fn Fn b) i==exp B RTarrow_forwardTopic: Photochemistry and Photophysics of Supramoleculesarrow_forwardTwo cations that exchange an electron in an interface, the exchange density is worth 1.39 mA/cm2 and the current density is worth 15 mA/cm2 at 25°C. If the overvoltage is 0.14 V, calculate the reaction rate and symmetry factor. Data: R = 8,314 J mol-1 k-1: F = 96500 Carrow_forward
- With the help of the Tafel line, it is estimated that the interchange density of the VO2+/VO2+ system on the carbon paper has a value of 3 mA cm-2. Calculate a) the current density if the voltage has a value of 1.6 mV and the temperature is 25°C. b) the beta value of the anódico process if the Tafel pendulum is 0.6 V at 25°C. Data: R = 8.314 JK-1mol-1, y F = 96485 C mol-1.arrow_forwardApply the NANSTE law to the MnO4- + 8H+ + 5e- ⇄ Mn2+ + 4H2Oarrow_forwardIn the Nernst Law, how much is RT / F?arrow_forward
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