FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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Steady-state operating data are shown in the figure below for an open feedwater heater. Heat transfer from
the feedwater heater to its surroundings occurs at an average outer surface temperature of 50°C at a rate of
100 kW. Ignore the effects of motion and gravity and let To = 25°C, po = 1 bar. Determine
(a) the ratio of the incoming mass flow rates, m/ṁ2.
(b) the rate of exergy destruction, in kW.
P2 = 1 bar
Tz = 400°C
1
ṁy = 0.7 kg/s
Pi = 1 bar
T, = 40°C
Feedwater heater
X3 = 25%
P3 = 1 bar
Tp = 50°C
%3D
2)
The gasoline internal combustion engine operates in a cycle consisting of six parts. Four of these
parts involve, among other things, friction, heat exchange through finite temperature differences, and
accelerations of the piston; it is irreversible. Nevertheless, it is represented by the ideal reversible Otto
cycle with a pV-diagram as illustrated below. The working substance of the cycle is assumed to be air.
PA
Q1
D
B
Q2
Ро
V
V8 = Vc
VA = VD
Three sub steps of a thermodynamic cycle are employed in order to change the state of
a gas from 1 bar, 1.5 cubic meter and internal energy of 512 kJ. The processes are:
1st step: Compression at constant PV to a pressure of 2 bar and internal energy of 690 kJ.
2nd step: A process where work transferred is zero and heat transferred is - 150 kJ.
3rd step: A process where work transferred is -50 kJ.
without KE and PE changes, determine:
a. heat transferred during 1st step (kJ)
b. heat transferred during 3rd step (kJ)
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- Determine the change in exergy in kJ for each of the following processes in the system with 1 kg of steam at 20 bar and 240 °C initially. a) In case the system is heated to double its volume at constant pressure. b) In case of expansion by doubling the system volume isothermally. dead state; T0=20 °C, P0=1 bararrow_forwardAt steady state, a refrigeration cycle removes 800 kJ/min of energy by heat transfer from acold space maintained at -15o C and discharges energy by heat transfer to its surroundings at20o C. If the coefficient of performance of the actual cycle is 80 percent of that of areversible refrigeration cycle (ideal) operating between thermal reservoirs at these twotemperatures (β = 0.80 βmax), determine:a) Coefficient of performance;b) Power input to the cycle, in kW;c) Heat rejected to the surroundings.Draw sketch and show all calculations.arrow_forwardWhen T > T0, the exergy and heat transfer are in the same direction.arrow_forward
- A power cycle operating between two reservoirs receives energy Qu by heat transfer from a hot reservoir at TH = 2000 K and rejects energy Qc by heat transfer to a cold reservoir at Tc = 400 K. For the cases below you will be asked to determine the cycle n and whether the cycle operates Reversibly, Irreversibility, or is Impossible. Сycle Сycle Сycle Assume: п — пСarnot n пСarnot 1. The maximum thermal efficiency nCarnot for the cycle is equal to а. 0.2 b. 0.8 с. 1.0 d. none of the above. 2. If QH = 1100 kJ and the Weycle = 900 kJ then the cycle is Reversible b. Irreversible c. Impossible а. d. none of the above. 3. If QH = 1000 kJ and Qc = 200 kJ then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above. 4. If Wq a. Reversible b. Irreversible c. Impossible d. none of the above. суcle 1400 kJ and Qc= 600 kJ then the cycle is 5. If n = 50% then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above.arrow_forwardA system executes a power cycle while receiving 1000 Btu by heat transfer at a temperature of 900oR and discharging 600 Btu by heat transfer at a temperature of 540oR. There are no other heat transfers.Determine the cycle thermal efficiency. Use the Clausius Inequality to determine σcycle, in Btu/oR. Determine if this cycle is internally reversible, irreversible, or impossible.arrow_forwardTwo reversible power cycles are arranged in series. The first cycle receives energy by heat transfer from a reservoir at temperature TH and rejects energy to a reservoir at an intermediate temperature T. The second cycle receives the energy rejected by the first cycle from the reservoir at temperature T and rejects energy to a reservoir at temperature TC lower than T. Derive an expression for the intermediate temperature T in terms of TH and TC when,a. The net works of the two power cycles are equalb. The thermal efficiencies of the two power cycles are equalarrow_forward
- Which of the following statements best describes the 2nd law of thermodynamics? The total entropy of a a reservoir must stay the same or increase. The change in internal energy for an ideal gas is given as A U=mc _▲T. V Heat energy will always be transferred from a hotter object to a colder object. Around a complete cycle, the net heat and net work additions must sum to zero. O A reversible cyclic engine can convert all the heat input it receives into useful work output.arrow_forwardA system executes a power cycle while receiving 900 Btu by heat transfer at a temperature of 900°R and discharging 800 Btu by heat transfer at a temperature of 540°R. There are no other heat transfers. Determine the cycle thermal efficiency. Use the Clausius Inequality to determine Ocycle, in Btu/°R. Determine if this cycle is internally reversible, irreversible, or impossible. Step 1 Determine the cycle thermal efficiency. n = i %arrow_forwardExergy flow associated with a fluid stream when the fluid properties are variable can be determined by.arrow_forward
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