The reason of lone pair occupying at equatorial position should be described. Concept introduction: The electrons involved in bond formation for any compound are known as bond pair and the electrons remained unused in bonding are known as lone pairs. As per the VSEPR theory, any molecule should have minimum energy and minimum repulsion states. It means that, the bonds should be arranged in such manner which could minimize the electronic repulsion and stabilize the molecules. Further, the axial positions are the positions parallel to the axes and the equitorial positions are perpendicular to the axes and lie on the equator.
The reason of lone pair occupying at equatorial position should be described. Concept introduction: The electrons involved in bond formation for any compound are known as bond pair and the electrons remained unused in bonding are known as lone pairs. As per the VSEPR theory, any molecule should have minimum energy and minimum repulsion states. It means that, the bonds should be arranged in such manner which could minimize the electronic repulsion and stabilize the molecules. Further, the axial positions are the positions parallel to the axes and the equitorial positions are perpendicular to the axes and lie on the equator.
Solution Summary: The author explains that the lone pair is positioned at equatorial position rather than axial position, to minimize the electronic repulsion and stabilize the molecules.
9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer
appropriately in the box. Only the answer in the box will be graded. (3) points)
OH
OH
بر بد بدید
2
3
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
Chapter 7 Solutions
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