FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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7.58 Figure PZ.58 shows a gas turbine power plant using air as the working fluid. The accompanying table gives steady-state
operating data. Air can be modeled as an ideal gas. Stray heat transfer and the effects of motion and gravity can be ignored
Let To 290 K, po = 100 kPa. Determine, each in kJ per kg of air flowing, (a) the net power developed, (b) the net exergy
increase of the air passing through the heat exchanger, (eg- e), and (c) a full exergy accounting based on the exergy
supplied to the plant found in part (b). Comment.
State p(kPa) T(K) h(kJ/kg) s° (kJ/kg K)
1100 290 290.16
1.6680
500 505 508.17
2
2.2297
3 500 875 904.99
2.8170
4 100 635 643.93
2.4688
a o is the variable appearing in Eq. 6.20a and Table A-22.
Heat exchanger
Compressor
Turbine
FIGURE P7.58
7.27 Figure P7.27 provides steady-state data for the outer wall of a dwelling on a day
when the indoor temperature is maintained at 25°C and the outdoor temperature is
35°C. The heat transfer rate through the wall is 1000 W. Determine, in W, the rate of
exergy destruction (a) within the wall, and (b) within the enlarged system shown on the
figure by the dashed line. Comment. Let T₂ = 35°C. 20.13, 33-56
Indoor
Boundary of
enlarged-
temperature=25°C
T=27C
T-3C
FIGURE PLAT
Outdoor
temperature=35°C
7.66 Referring to the discussion of Sec. Z.6.2 as required, evaluate the exergetic efficiency for each of the following cases,
assuming steady-state operation with negligible effects of heat transfer with the surroundings:
a. Turbine: Wer 1200 hp, e 250 Btu//lb, eg = 15 Btu/lb, m 240 lb/min.
b. Compressor: Wev/m=-105 kJ /kg, e = 5 kJ/kg, eg = 90 kJ/kg, m 2 kg /s.
c. Counterflow heat exchanger: mh = 3 kg/s, me 10 kg /s, ef = 2100 kJ/kg, e = 300 kJ/kg, É = 3.4 MW
10 lb /s, m3 15 b /s, en = 1000 Btu/Ib, eg = 50 Btu/Ib, eg = 400 Btu/lb
d. Direct contact heat exchanger: m1
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- 6.110 Figure P6.110 shows a simple vapor power plant operating at steady state with water as the working fluid. Data at key locations are given on the figure. The mass flow rate of the water circulating through the components is 109 kg/s. Stray heat transfer and kinetic and potential energy effects can be ignored. Determine a. the net power developed, in MW. b. the thermal efficiency. c. the isentropic turbine efficiency. t2 d. the isentropic pump efficiency. e. the mass flow rate of the cooling water, in kg/s. f. the rates of entropy production, each in kW/K, for the turbine, condenser, and pump. P = 100 bar T = 520°C %3D Power out Turbine P2 = 0.08 bar 2 = 90% %3D Steam Cooling water in at 20°C generator Condenser Pa= 100 bar T= 43°C Cooling water out at 35°C 4. Pump 3 P3 0.08 bar Saturated liquid Power in FIGURE P6.110 2. wwwarrow_forwardFigure PZ55 and the accompanying table provide the schematic and steady-state operating data for a flash 7.55 chamber fitted with an inlet valve that produces saturated vapor and saturated liquid streams from a single entering stream of liquid water. Stray heat transfer and the effects of motion and gravity are negligible. Determine (a) the mass flow rate, in Ib/s, for each of the streams exiting the flash chamber and (b) the total rate of exergy destruction, in Btu/s. Let To = 77°F, Po =1 atm State Condition T(°F) p(lbf/in.°) h(Btu/lb) s(Btu/lb R) liquid 300 80 269.7 1 0.4372 1.6996 30 1164.3 2 sat. vapor 3 sat. liquid 218.9 0.3682 30 2 Saturated vapor P2=30 lbf/in.2 Flash chamber Valve =100 lb/s T 300°F P=80 lbf/in.2 Saturated liquid,A+ P3=30 lbf/in.2 3 FIGURE P7.55arrow_forwardLooking for help understanding the step I need to solve this.arrow_forward
- A domestic water heater holds 189 L of water at 60°C, 1 atm. Determine the exergy of the hot water, in kJ. To what elevation, in m, would a 1000-kg mass have to be raised from zero elevation relative to the reference environment for its exergy to equal that of the hot water? Let To = 298 K, po = 1 atm, g = 9.81 m/s².arrow_forwardA domestic water heater holds 189 L of water at 60°C, 1 atm. Determine the exergy of the hot water, in kJ. To what elevation, in m, would a 1000-kg mass have to be raised from zero elevation for its exergy to equal that of the hot water? Let T0 = 298 K, p0 = 1 atm, g = 9.81 m/s2 .arrow_forwardThermodynamics, please show all work. Step 1 and 2.arrow_forward
- A well-insulated turbine operating at steady state develops 20 MW of power for a steam flow rate of 50 kg/s. The steam enters at 5 bar with a velocity of 61 m/s and exits as saturated vapor at 0.06 bar with a velocity of 130 m/s. Neglecting potential energy effects, determine the inlet temperature, in °C. T₁= i eTextbook and Media Save for Later °℃ Attempts: 0 of 5 used Submit Answerarrow_forwardThermodynamics, please help and show all work please.arrow_forwardanswer 99 and 100arrow_forward
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