Chapter 7, Problem 7.43P

Q.6.A. Oxygen enters a nozzle with a negligible velocity at 440 K and 12 bar, and leaves at 1.9 bar. Determine the volumetric flow rate of the oxygen at the nozzle entrance if the nozzle exit area is 2.5 cm2 and the ratio of inlet temperature to the outlet equal 1.69. (Cy = 718 J/kg K and Cp = 1005 J/kg K)

Determine the change in specific entropy, in kJ/kg K, of CO2 as an ideal gas undergoing a process from T, = 300 K, p, = 1 bar to T2 = 1420 K. P2 = 5 bar. Additional information g°= 1.70203 KJKG K °2 = 3.37901 kJikg K 1.215 kJ/kg. °C 1.215 kJkg. K 0 1.190 kJ/kg K O 1.373 kJ/kg K

Air with initial state at 12500 ft is allowed to expand isentropically to a state where pressure is 1100 psf. Calculate the specific weight after the expansion. a. 4.58x10^-3 lb/ft^3   b. 0.0458 lb/ft^3   c. 0.0458x10^-2 lb/ft^3   d. 0.0575 lb/ft^3   e. 458 lb/ft^3

4 An air nozzle has an efficiency of .90 and is adiabatic. air enters at p1=200 kPa, T1=1300 K with negligible velocity. air exits at p2=130 kPa. use dead state variables of T0=293 k and P0= 100 kPa and a variable heat capacity. what is t2 and the rate of exergy destruction?

use table Table Derive expressions for the heat absorbed by the system for each of the following classes of reversible processes for one mole of an idea gas: (a) Case 1: Isothermal change in pressure (b) Case 2: Isobaric change in volume Hint: Case 1 with S = S(T,P); Case 2 with S = S(P,V) (c) Case 3: Isochoric (constant volume) change in temperature dV=Va dT-VB AP dS=CT dT-Va dP dU= (Cp-PVα) dT + V(PB - Ta) dP dH=Cp dT +V(I-Ta) dP dF=-(S+PVa) dT + VPB dP dG=-S dT + V dP

A Gas enters an engine cylinder with volumetric analysis as follows: Oxygen =12.5%, Carbon Dioxide = 13% and nitrogen =74.5%.at the beginning of expansion, the temperature is 550° C, then expands reversibly with final to initial volume ratio of 6:1. If the process follows PV^1.25 = C, Calculate the heat flow in kJ/kg

Correct answer will be upvoted.THANK YOU!!!

The work required to compress a gas reversibly according to pV^1.30 = C is 67,790 J, if there is no flow. Determine change in U (in kJ) and Q (in kJ) if the gas is methane. For methane, k = 1.321, R = 518.45J/kg·K, cv = 1.6187, cp = 2.1377 J/kg·K. And also draw the P-V and T-S diagrams.

Answer 94 and 95