Principles of Foundation Engineering, SI Edition
8th Edition
ISBN: 9781305723351
Author: Braja M. Das
Publisher: Cengage Learning US
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Chapter 7, Problem 7.3P
To determine
Find the value of elastic settlement at the center of the area loaded.
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A circular Beam with roller joint
R
L
y
y
oo = 298.6055 Pa
Ro
= 2.0649 m
L = 61 m
Material Data
E[ GPA]
Oyp [MPa]
p [kg/m^3
V
200
0.3
700
7800
Find: Displacement in X, Y, Z direction, von misses stress, tresca stress, and triaxial stress
at x = L, at x = L/2 and x = 0. Please show all work
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Chapter 7 Solutions
Principles of Foundation Engineering, SI Edition
Ch. 7 - Prob. 7.1PCh. 7 - A planned flexible load area (see Figure P7.2) is...Ch. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Solve Problem 7.8 using Eq. (7.29). Ignore the...Ch. 7 - A continuous foundation on a deposit of sand layer...
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- Part A Replace the loading by an equivalent resultant force and couple moment acting at point O. (Eigure 1) Determine the equivalent resultant force. Express your answer in terms of the variables wg, L, and constant r. ν ΑΣφ vec ? Fr = Submit Request Answer Part B Determine the couple moment. Express your answer in terms of the variables wo, L, and constant 7. Figure V ΑΣφ vec ? (Mr)o = Submit Request Answer W cos() Provide Feedbackarrow_forwardPROBLEM 1: The homogeneous structure shown weighs 21.45 kN per square meter of cross-section. The structure is subject to horizontal uniformly distributed load P1 and triangularly distributed load P2 perpendicular to side AB. Given: H1 = 9 m; H2 = 6 m; H3 = 12 m X1 = 6 m; X2 = 5 m P1 = 220 kN/m; P2 = 280 kN/m Required Answer Equivalent force of uniform load P1 1980.00 Total weight of the structure, W 3603.60 Horizontal component of the resultant, Rx 300.00arrow_forwardA simply supported beam 4 m long has a cross section shown. Determine the maximum uniformly distributed load which can be applied over the entire length of the beam if the shearing stress is limited to 1.3 MPa. Answer must be in kN/m. Given: b = 120 mm and d = 180 mm.arrow_forward
- 4. A beam of rectangular cross section 40 mm by 100 mm is carrying a bending moment of M = 21 kN.m about its strong axis. Determine the residual stresses following removal of the bending moment (show the residual stress distribution). Consider oy = 240 MPa, and E = 200 GPa. Solution: 100 mm 40 mmarrow_forwardThe velocity gradient is 1000 m/s. The viscosity u= is 1.2*10^-4* N-s/(m^2). The shear stress is (a) 0.12 N/m² (b) 12N/ (m^2) (c) 1.2x 107 N/m² (d) 12 * 10^-5 * N/(m^2)arrow_forwardA rectangular distributed load of 100 kPa is applied to the soil surface. An additional circular distributed load of 200 kPa is applied on one side of the previous load. Determine the vertical effective stress 6 m below point A due to the application of both loads. R= 6 m 6 m 6 m 6 m 200 kPa 6 m 6 m 100 kPa 6 marrow_forward
- Numerical Analysis (HW. #1) The vertical stress increment (Ao) due to a point load acting on the surface of linearly elastic medium is given as: 3P23 Ao 27Vr? + z? where P is the magnitude of the load, r is the lateral distance, and z is the depth of the point where the stress is to be calculated. If P = 10g kN and r = using two methods: fixed-point and Newton-Raphson method) the depth z at which the stress increment Ao = 10n kN/m?. (Take g=student group number A=1, B=2, 1.5 m, determine (by C=3, D=4, and E=5, n=student number in his/her group, and & =1x10-6)arrow_forwardStresses in soilarrow_forwardA simply supported beam 4 m long has a cross section shown. Determine the maximum uniformly distributed load which can be applied over the entire length of the beam if the shearing stress is limited to 1.8 MPa. Answer must be in kN/m. Given: b = 110 mm and d= 170 mm. 260 mm 150 mmarrow_forward
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