Given the following data Ca ( s ) + 2 C ( g r a p h i t e ) → CaC 2 ( s ) Δ H = − 62.8 KJ Ca ( s ) + 1 2 O 2 ( g ) → CaO ( s ) Δ H = − 635.5 KJ CaO ( s ) + H 2 O ( l ) → Ca ( OH ) 2 ( a q ) Δ H = − 653.1 KJ C 2 H 2 ( g ) + 5 2 O 2 ( g ) → 2 CO 2 ( g ) + H 2 O ( l ) Δ H = − 1300. KJ C ( g r a p h i t e ) + O 2 ( g ) → CO 2 ( g ) Δ H = − 393.5 KJ Calculate ∆ H for the reaction CaC 2 ( s ) + 2 H 2 O ( l ) → Ca ( OH ) 2 ( a q ) + C 2 H 2 ( g )
Given the following data Ca ( s ) + 2 C ( g r a p h i t e ) → CaC 2 ( s ) Δ H = − 62.8 KJ Ca ( s ) + 1 2 O 2 ( g ) → CaO ( s ) Δ H = − 635.5 KJ CaO ( s ) + H 2 O ( l ) → Ca ( OH ) 2 ( a q ) Δ H = − 653.1 KJ C 2 H 2 ( g ) + 5 2 O 2 ( g ) → 2 CO 2 ( g ) + H 2 O ( l ) Δ H = − 1300. KJ C ( g r a p h i t e ) + O 2 ( g ) → CO 2 ( g ) Δ H = − 393.5 KJ Calculate ∆ H for the reaction CaC 2 ( s ) + 2 H 2 O ( l ) → Ca ( OH ) 2 ( a q ) + C 2 H 2 ( g )
Solution Summary: The author defines enthalpy change as amount of heat absorbed or released in chemical reactions at constant pressure.
Ca
(
s
)
+
2
C
(
g
r
a
p
h
i
t
e
)
→
CaC
2
(
s
)
Δ
H
=
−
62.8
KJ
Ca
(
s
)
+
1
2
O
2
(
g
)
→
CaO
(
s
)
Δ
H
=
−
635.5
KJ
CaO
(
s
)
+
H
2
O
(
l
)
→
Ca
(
OH
)
2
(
a
q
)
Δ
H
=
−
653.1
KJ
C
2
H
2
(
g
)
+
5
2
O
2
(
g
)
→
2
CO
2
(
g
)
+
H
2
O
(
l
)
Δ
H
=
−
1300.
KJ
C
(
g
r
a
p
h
i
t
e
)
+
O
2
(
g
)
→
CO
2
(
g
)
Δ
H
=
−
393.5
KJ
Calculate ∆H for the reaction
CaC
2
(
s
)
+
2
H
2
O
(
l
)
→
Ca
(
OH
)
2
(
a
q
)
+
C
2
H
2
(
g
)
Draw the titration curve of (i) weak acid vs. strong base; (ii) weak acid vs. weakbase; (iii) diprotic acid with strong base (iii) triprotic acid with strong base.
Complete the reaction in the drawing area below by adding the major products to the right-hand side.
If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead.
Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule
to represent each pair of enantiomers, using line bonds at the chiral center.
More...
No reaction.
my
ㄖˋ
+
1. Na O Me
Click and drag to start
drawing a structure.
2. H
+
Predict the intermediate 1 and final product 2 of this organic reaction:
NaOMe
H+
+
1
2
H
H
work up
You can draw 1 and 2 in any arrangement you like.
Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center.
Click and drag to start drawing a structure.
X
$
dm
Chapter 7 Solutions
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