GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
7th Edition
ISBN: 9781305866966
Author: STOKER
Publisher: CENGAGE L
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Chapter 7, Problem 7.35EP

(a)

Interpretation Introduction

Interpretation:

The volume in liters for a sample of carbon dioxide gas at given set of conditions by using combined gas law has to be determined.

Concept Introduction:

Combined gas law tells that the Kelvin temperature of gas is directly proportional to the pressure and volume of a fixed amount of gas.  The mathematical expression for combined gas law can be represented as follows,

P1V1T1=P2V2T2

(a)

Expert Solution
Check Mark

Explanation of Solution

Record the given data,

P1=1.35atmV1=15.2LT1=33°Cconvertedto306KP2=3.50atmT2=35°Cconvertedto308KV2=?

Now, substitute these values in rearranged combined gas law and do some simple mathematical calculation to gent final answer as follows,

V2=V1×P1P2×T2T1

V2=15.2L×(1.35atm3.50atm)×(308K306K)=5.90L

The final volume in liters for a sample of carbon dioxide gas at given set of conditions is 5.90L.

(b)

Interpretation Introduction

Interpretation:

The pressure in atmospheres for a sample of carbon dioxide gas at given set of conditions by using combined gas law has to be determined.

Concept Introduction:

Combined gas law tells that the Kelvin temperature of gas is directly proportional to the pressure and volume of a fixed amount of gas.  The mathematical expression for combined gas law can be represented as follows,

P1V1T1=P2V2T2

(b)

Expert Solution
Check Mark

Explanation of Solution

Record the given data,

P1=1.35atmV1=15.2LT1=33°Cconvertedto306KP2=?T2=42°Cconvertedto315KV2=10.0L

Now, substitute these values in rearranged combined gas law and do some simple mathematical calculation to gent final answer as follows,

P2=P1×V1V2×T2T1

P2=1.35 atm×(15.2 L10.0 L)×(315 K306 K)=2.11atm

The final pressure in atmosphere for a sample of carbon dioxide gas at given set of conditions is 2.11atm.

(c)

Interpretation Introduction

Interpretation:

The temperature in degree Celsius for a sample of carbon dioxide gas at given set of conditions by using combined gas law has to be determined.

Concept Introduction:

Combined gas law tells that the Kelvin temperature of gas is directly proportional to the pressure and volume of a fixed amount of gas.  The mathematical expression for combined gas law can be represented as follows,

P1V1T1=P2V2T2

(c)

Expert Solution
Check Mark

Explanation of Solution

Record the given data,

P1=1.35atmV1=15.2LT1=33°Cconvertedto306KP2=7.00atmT2=?V2=0.973L

Now, substitute these values in rearranged combined gas law and do some simple mathematical calculation to gent final answer as follows,

T2=T1×V2V1×P2P1

T2=306K×(7.00atm1.35atm)×(0.973L15.2L)=102K

The obtained pressure is in Kelvin units now we have to convert this value into degree Celsius as follows,

T273

102273=171°C

The final temperature in degree Celsius for a sample of carbon dioxide gas at given set of conditions is 171°C.

(a)

Interpretation Introduction

Interpretation:

The volume in milliliters for a sample of carbon dioxide gas at given set of conditions by using combined gas law has to be determined.

Concept Introduction:

Combined gas law tells that the Kelvin temperature of gas is directly proportional to the pressure and volume of a fixed amount of gas.  The mathematical expression for combined gas law can be represented as follows,

P1V1T1=P2V2T2

(a)

Expert Solution
Check Mark

Explanation of Solution

Record the given data,

P1=1.35atmV1=15.2Lconvertedto15200mLT1=33°Cconvertedto306KP2=6.70atmT2=97°Cconvertedto370KV2=?

Now, substitute these values in rearranged combined gas law and do some simple mathematical calculation to gent final answer as follows,

V2=V1×P1P2×T2T1

V2=15200mL×(1.35atm6.70atm)×(370K306K)=3.70×103mL

The final volume in liters for a sample of carbon dioxide gas at given set of conditions is 3.70×103mL.

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Chapter 7 Solutions

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP

Ch. 7.4 - Prob. 2QQCh. 7.4 - Based on Boyles law, if the pressure on 30.0 mL of...Ch. 7.5 - Prob. 1QQCh. 7.5 - Prob. 2QQCh. 7.5 - Prob. 3QQCh. 7.6 - Prob. 1QQCh. 7.6 - Prob. 2QQCh. 7.6 - Prob. 3QQCh. 7.7 - Prob. 1QQCh. 7.7 - Prob. 2QQCh. 7.7 - Prob. 3QQCh. 7.7 - Prob. 4QQCh. 7.8 - Prob. 1QQCh. 7.8 - Prob. 2QQCh. 7.8 - Prob. 3QQCh. 7.9 - Prob. 1QQCh. 7.9 - Prob. 2QQCh. 7.9 - Prob. 3QQCh. 7.10 - Prob. 1QQCh. 7.10 - Prob. 2QQCh. 7.10 - Prob. 3QQCh. 7.11 - Prob. 1QQCh. 7.11 - Prob. 2QQCh. 7.11 - Prob. 3QQCh. 7.11 - Prob. 4QQCh. 7.11 - Prob. 5QQCh. 7.11 - Prob. 6QQCh. 7.12 - Prob. 1QQCh. 7.12 - Prob. 2QQCh. 7.12 - Prob. 3QQCh. 7.13 - Prob. 1QQCh. 7.13 - Prob. 2QQCh. 7.13 - Prob. 3QQCh. 7.13 - Prob. 4QQCh. 7.13 - Prob. 5QQCh. 7.13 - Prob. 6QQCh. 7 - Indicate whether each of the following statements...Ch. 7 - Indicate whether each of the following statements...Ch. 7 - Prob. 7.3EPCh. 7 - Prob. 7.4EPCh. 7 - Prob. 7.5EPCh. 7 - Prob. 7.6EPCh. 7 - Prob. 7.7EPCh. 7 - Prob. 7.8EPCh. 7 - Prob. 7.9EPCh. 7 - Prob. 7.10EPCh. 7 - Prob. 7.11EPCh. 7 - Prob. 7.12EPCh. 7 - Prob. 7.13EPCh. 7 - Prob. 7.14EPCh. 7 - Prob. 7.15EPCh. 7 - Prob. 7.16EPCh. 7 - Prob. 7.17EPCh. 7 - Prob. 7.18EPCh. 7 - A sample of ammonia (NH3), a colorless gas with a...Ch. 7 - A sample of nitrogen dioxide (NO2), a toxic gas...Ch. 7 - Prob. 7.21EPCh. 7 - Prob. 7.22EPCh. 7 - Prob. 7.23EPCh. 7 - Prob. 7.24EPCh. 7 - Prob. 7.25EPCh. 7 - Prob. 7.26EPCh. 7 - A sample of N2 gas occupies a volume of 375 mL at...Ch. 7 - A sample of Ar gas occupies a volume of 1.2 L at...Ch. 7 - Prob. 7.29EPCh. 7 - Prob. 7.30EPCh. 7 - Prob. 7.31EPCh. 7 - Prob. 7.32EPCh. 7 - Prob. 7.33EPCh. 7 - Prob. 7.34EPCh. 7 - Prob. 7.35EPCh. 7 - Prob. 7.36EPCh. 7 - Prob. 7.37EPCh. 7 - Prob. 7.38EPCh. 7 - Prob. 7.39EPCh. 7 - Prob. 7.40EPCh. 7 - Prob. 7.41EPCh. 7 - Prob. 7.42EPCh. 7 - Prob. 7.43EPCh. 7 - Prob. 7.44EPCh. 7 - Prob. 7.45EPCh. 7 - Prob. 7.46EPCh. 7 - Prob. 7.47EPCh. 7 - Prob. 7.48EPCh. 7 - Prob. 7.49EPCh. 7 - Prob. 7.50EPCh. 7 - Determine the following for a 0.250-mole sample of...Ch. 7 - Determine the following for a 0.500-mole sample of...Ch. 7 - Prob. 7.53EPCh. 7 - Prob. 7.54EPCh. 7 - Prob. 7.55EPCh. 7 - What is the value of the ideal gas constant R if...Ch. 7 - The total pressure exerted by a mixture of O2, N2,...Ch. 7 - The total pressure exerted by a mixture of He, Ne,...Ch. 7 - A gas mixture contains O2, N2, and Ar at partial...Ch. 7 - A gas mixture contains He, Ne, and H2S at partial...Ch. 7 - Prob. 7.61EPCh. 7 - Prob. 7.62EPCh. 7 - Prob. 7.63EPCh. 7 - Prob. 7.64EPCh. 7 - Prob. 7.65EPCh. 7 - Prob. 7.66EPCh. 7 - Prob. 7.67EPCh. 7 - Prob. 7.68EPCh. 7 - Prob. 7.69EPCh. 7 - Prob. 7.70EPCh. 7 - Prob. 7.71EPCh. 7 - Prob. 7.72EPCh. 7 - What are the two ways in which the escape of...Ch. 7 - Prob. 7.74EPCh. 7 - Prob. 7.75EPCh. 7 - How does an increase in the surface area of a...Ch. 7 - Prob. 7.77EPCh. 7 - Prob. 7.78EPCh. 7 - Prob. 7.79EPCh. 7 - Prob. 7.80EPCh. 7 - Prob. 7.81EPCh. 7 - What is the relationship between the strength of...Ch. 7 - What term is used to describe a substance that...Ch. 7 - Prob. 7.84EPCh. 7 - Indicate whether each of the following statements...Ch. 7 - Indicate whether each of the following statements...Ch. 7 - Prob. 7.87EPCh. 7 - What is the relationship between location...Ch. 7 - Prob. 7.89EPCh. 7 - Prob. 7.90EPCh. 7 - Indicate whether or not each of the following...Ch. 7 - Prob. 7.92EPCh. 7 - Prob. 7.93EPCh. 7 - Prob. 7.94EPCh. 7 - For liquid-state samples of the following diatomic...Ch. 7 - For liquid-state samples of the following diatomic...Ch. 7 - Prob. 7.97EPCh. 7 - Prob. 7.98EPCh. 7 - Prob. 7.99EPCh. 7 - Prob. 7.100EPCh. 7 - Prob. 7.101EPCh. 7 - Prob. 7.102EPCh. 7 - Prob. 7.103EPCh. 7 - Prob. 7.104EPCh. 7 - Prob. 7.105EPCh. 7 - Prob. 7.106EP
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