(a) Explanation Given info: The mass of the wooden crate is 35.0 kg , the displacement of the crate is 12.0 m and the work by the force on the crate is 350 J . The work done by the applied force is, W = F Δ r cos θ (1) Here, F is the force exerted on the crate. Δ r is the displacement of the crate. θ is the angle between force vector and displacement vector. The force exerted on the crate is along the horizontal direction so the angle between the force vector and displacement vector is 0 . The value of angle is, cos θ = cos 0 ° = 1 Substitute 350 J for W , 12 (b) To determine The subsequent motion of the crate when applied force is greater than F . (c) To determine The subsequent motion of the crate when applied force is less than F .

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Author: Jewett

Publisher: CENGAGE LEARNING - CONSIGNMENT

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Chapter 7, Problem 7.32P

(a)

To determine

The value of force.

(b)

To determine

The subsequent motion of the crate when applied force is greater than F .

(c)

To determine

The subsequent motion of the crate when applied force is less than F .

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Chapter 7, Problem 7.31P

Chapter 7, Problem 7.33P

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Chapter 7 Solutions

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The value of force.

Solution Summary: The author explains that the value of force is 29.2n.

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The value of force.

The subsequent motion of the crate when applied force is greater than F .

The subsequent motion of the crate when applied force is less than F .

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Chapter 7 Solutions