ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
7th Edition
ISBN: 9781319403959
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 7, Problem 7.2E
Interpretation Introduction
Interpretation:
The effect of temperature on the ratio of
Concept Introduction:
The activation energy is the minimum amount of energy which is needed for the formation of product by crossing the energy barrier at which transition state formed. The use of catalyst reduces the activation energy which results in the increase of the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Technetium is the first element in the periodic chart that does not have any stable isotopes.
Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half
life ideally suited for medical tests. It would seem that the decay of technetium should fit the
treatment above with the result In(c/c) = -kt. The table below includes data from the two sites:
http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130
http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab).
a.
b.
C.
Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also
graph In(c/c.) on the vertical axis versus time on the horizontal axis.
When half of the original amount of starting material has hours fraction remaining
disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes
In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the
material to decay away). Determine the slope of your In(c/c.) vs
t graph and…
Please correct answer and don't use hand rating
1.
a) Assuming that an atom of arsenic has hydrogen-like atomic orbitals, sketch the radial
probability plots for 4p and 4d orbitals of S atom. Indicate angular and radial nodes in
these orbitals.
(4 points)
b) Calculate Zeff experienced by and electron in 4p AO's in a arsenic atom. Use Slater rules
that were discussed in lecture.
(3 points)
Chapter 7 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
Ch. 7 - Prob. 7A.1ASTCh. 7 - Prob. 7A.1BSTCh. 7 - Prob. 7A.2ASTCh. 7 - Prob. 7A.2BSTCh. 7 - Prob. 7A.3ASTCh. 7 - Prob. 7A.3BSTCh. 7 - Prob. 7A.4ASTCh. 7 - Prob. 7A.4BSTCh. 7 - Prob. 7A.1ECh. 7 - Prob. 7A.2E
Ch. 7 - Prob. 7A.3ECh. 7 - Prob. 7A.4ECh. 7 - Prob. 7A.7ECh. 7 - Prob. 7A.8ECh. 7 - Prob. 7A.9ECh. 7 - Prob. 7A.10ECh. 7 - Prob. 7A.11ECh. 7 - Prob. 7A.12ECh. 7 - Prob. 7A.13ECh. 7 - Prob. 7A.14ECh. 7 - Prob. 7A.15ECh. 7 - Prob. 7A.16ECh. 7 - Prob. 7A.17ECh. 7 - Prob. 7A.18ECh. 7 - Prob. 7B.1ASTCh. 7 - Prob. 7B.1BSTCh. 7 - Prob. 7B.2ASTCh. 7 - Prob. 7B.2BSTCh. 7 - Prob. 7B.3ASTCh. 7 - Prob. 7B.3BSTCh. 7 - Prob. 7B.4ASTCh. 7 - Prob. 7B.4BSTCh. 7 - Prob. 7B.5ASTCh. 7 - Prob. 7B.5BSTCh. 7 - Prob. 7B.1ECh. 7 - Prob. 7B.2ECh. 7 - Prob. 7B.3ECh. 7 - Prob. 7B.4ECh. 7 - Prob. 7B.5ECh. 7 - Prob. 7B.6ECh. 7 - Prob. 7B.7ECh. 7 - Prob. 7B.8ECh. 7 - Prob. 7B.9ECh. 7 - Prob. 7B.10ECh. 7 - Prob. 7B.13ECh. 7 - Prob. 7B.14ECh. 7 - Prob. 7B.15ECh. 7 - Prob. 7B.16ECh. 7 - Prob. 7B.17ECh. 7 - Prob. 7B.18ECh. 7 - Prob. 7B.19ECh. 7 - Prob. 7B.20ECh. 7 - Prob. 7B.21ECh. 7 - Prob. 7B.22ECh. 7 - Prob. 7C.1ASTCh. 7 - Prob. 7C.1BSTCh. 7 - Prob. 7C.2ASTCh. 7 - Prob. 7C.2BSTCh. 7 - Prob. 7C.1ECh. 7 - Prob. 7C.2ECh. 7 - Prob. 7C.3ECh. 7 - Prob. 7C.4ECh. 7 - Prob. 7C.5ECh. 7 - Prob. 7C.6ECh. 7 - Prob. 7C.7ECh. 7 - Prob. 7C.8ECh. 7 - Prob. 7C.9ECh. 7 - Prob. 7C.11ECh. 7 - Prob. 7C.12ECh. 7 - Prob. 7D.1ASTCh. 7 - Prob. 7D.1BSTCh. 7 - Prob. 7D.2ASTCh. 7 - Prob. 7D.2BSTCh. 7 - Prob. 7D.1ECh. 7 - Prob. 7D.2ECh. 7 - Prob. 7D.3ECh. 7 - Prob. 7D.5ECh. 7 - Prob. 7D.6ECh. 7 - Prob. 7D.7ECh. 7 - Prob. 7D.8ECh. 7 - Prob. 7E.1ASTCh. 7 - Prob. 7E.1BSTCh. 7 - Prob. 7E.1ECh. 7 - Prob. 7E.2ECh. 7 - Prob. 7E.3ECh. 7 - Prob. 7E.4ECh. 7 - Prob. 7E.5ECh. 7 - Prob. 7E.6ECh. 7 - Prob. 7E.7ECh. 7 - Prob. 7E.8ECh. 7 - Prob. 7E.9ECh. 7 - Prob. 1OCECh. 7 - Prob. 7.1ECh. 7 - Prob. 7.2ECh. 7 - Prob. 7.3ECh. 7 - Prob. 7.4ECh. 7 - Prob. 7.5ECh. 7 - Prob. 7.6ECh. 7 - Prob. 7.7ECh. 7 - Prob. 7.9ECh. 7 - Prob. 7.11ECh. 7 - Prob. 7.14ECh. 7 - Prob. 7.15ECh. 7 - Prob. 7.17ECh. 7 - Prob. 7.19ECh. 7 - Prob. 7.20ECh. 7 - Prob. 7.23ECh. 7 - Prob. 7.25ECh. 7 - Prob. 7.26ECh. 7 - Prob. 7.29ECh. 7 - Prob. 7.30ECh. 7 - Prob. 7.31E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- What is the pH of the Tris buffer after the addition of 10 mL of 0.01M NaOH? How would I calculate this?arrow_forwardWhy do isopolianions form polymeric species with a defined molecular weight? What does it depend on?arrow_forwardWhat are isopolianions? Describe the structural unit of isopolianions.arrow_forward
- Justify the polymerization of vanadates VO43-, as a function of concentration and pH.arrow_forwardWhat is the preparation of 500 mL of 100mM MOPS buffer (pH=7.5) starting with 1 M MOPS and 1 M NaOH? How would I calculate the math?arrow_forwardIndicate the correct option.a) Isopolianions are formed around metallic atoms in a low oxidation state.b) Non-metals such as N, S, C, Cl, ... give rise to polyacids (oxygenated).c) Both are incorrect.arrow_forward
- 14. Which one of the compounds below is the major organic product obtained from the following series of reactions? Br OH OH CH3O™ Na+ H*, H₂O SN2 HO OH A B C D 0 Earrow_forwardWavelength (nm) I'm not sure what equation I can come up with other than the one generated with my graph. Can you please show me the calculations that were used to find this equation? Give an equation that relates energy to wavelength. Explain how you arrived at your equation. Wavelength Energy (kJ/mol) (nm) 350 341.8 420 284.8 470 254.5 530 225.7 580 206.3 620 192.9 700 170.9 750 159.5 Energy vs. Wavelength (Graph 1) 400 350 y=-0.4367x+470.82 300 250 200 150 100 50 O 0 100 200 300 400 500 600 700 800 Energy (kJ/mol)arrow_forward5. Draw molecular orbital diagrams for superoxide (O2¯), and peroxide (O2²-). A good starting point would be MO diagram for O2 given in your textbook. Then: a) calculate bond orders in superoxide and in peroxide; indicate which species would have a stronger oxygen-oxygen bond; b) indicate which species would be a radical. (4 points)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Kinetics: Chemistry's Demolition Derby - Crash Course Chemistry #32; Author: Crash Course;https://www.youtube.com/watch?v=7qOFtL3VEBc;License: Standard YouTube License, CC-BY