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Engineering Computer Science MYPROGRAMMINGLAB WITH PEARSON ETEXT

Program plan: intvalue variables is used for input. void displayBits ( unsigned value ) function represents the passing integer value it equivalent bits form based on bytes allocates in a specific system Program description: The main purpose of the program is to display the bits form of an integer value based on the bytes allocated by the system. Program: #include <stdio.h> #include <conio.h> //function to print the grades of students voidprintdata(intexamdata[][4],int student,int subject); //function to find minimum grade voidmingrade(intexamdata[][4],int student,int subject); //function to find maximum grade voidmaxgrade(intexamdata[][4],int student,int subject); //function to calculate average grade voidgradeavg(intexamdata[][4],int student,int subject); void main() { //array to store the exam data intexamdata[3][4]; int m, n,ch; //array of pointer to function initialization void(*processGrades[4])(int[][4],int,int)= { printdata,mingrade,maxgrade,gradeavg }; clrscr(); //input the exam data of each student printf("Enter exam data for the students \n"); for(m =0; m <3; m++) { printf("\nEnter marks for student %d ", m +1); for(n =0; n <4; n++) { printf("\nsubject %d ", n +1); scanf("%d",&examdata[m][n]); } } //print the menu while(1) { clrscr(); printf("\n\n"); printf("Enter a choice: \n"); printf("\n0 Print array of grade"); printf("\n1 Find the minimum grade"); printf("\n2 Find the maximum grade"); printf("\n3 Print the average on all testes for each student"); printf("\n4 End program"); printf("\n?"); scanf("%d",&ch); //check if choiec is invalid if(ch>=0&&ch<=4) { //check to end of program if(ch==4) break; else //otherwise call the function // as choice entered by user (*processGrades[ch])(examdata,3,4); } else printf("\n Invalid Choice"); getch(); } } //function definition to print the student exam data voidprintdata(intexamdata[][4],int student,int subject) { int m,n; //print the headers printf("\n\t sub1 sub2 sub3 sub4\n"); //loop to get the data for(m =0; m < student; m++) { //print student number printf("Student %d\t", m +1); for(n =0; n < subject; n++) //print grade of student printf("%d ",examdata[m][n]); printf("\n"); } } //function definition to find minimum grade from the data voidmingrade(intexamdata[][4],int student,int subject) { int low, m,n; //set the highest grade low =100; for(m =0; m < student; m++) for(n =0; n < subject; n++) //check if low value is greater than current grade if(low >examdata[m][n]) //copy the low value low =examdata[m][n]; //print the lowest value printf("\n Minimum Grade is %d ", low); } //function definition to find maximum grade voidmaxgrade(intexamdata[][4],int student,int subject) { int high, m,n; //set the lowest value high =0; for(m =0; m < student; m++) for(n =0; n < subject; n++) //check if current high value is lower than current grade if(high <examdata[m][n]) //copy the higher grade high =examdata[m][n]; //print the highest grade printf("\n Maximum Grade is %d ", high); } //function definition to calculate average grade of each student voidgradeavg(intexamdata[][4],int student,int subject) { inttgrade, m,n; floatavg; for(m =0; m < student; m++) { //set the total grade to 0 tgrade=0; for(n =0; n < subject; n++) //add the grades of current student tgrade+=examdata[m][n]; //calculate the average avg =tgrade/(float)subject; //print the average of current student printf("\nStudent %d average grade is %.2f ", m +1, avg); } } Explanation: In the above code an integer value is input by the user. Then displayBits() function display the bits value of the input integer value. It first checks whether specific system allocates 4 bytes or 2 bytes to store the integer value. It then initializes the bitmask accordingly. A loop executes from 1 to total no of bits for that integer value. In each iteration integer bits are compared with the bitmask using bitwise AND operation to check whether current bit is 1 or 0 and print accordingly. To separate the bits in 8 bits group, after every 8 bit a space is inserted. Sample output:

Program plan: intvalue variables is used for input. void displayBits ( unsigned value ) function represents the passing integer value it equivalent bits form based on bytes allocates in a specific system Program description: The main purpose of the program is to display the bits form of an integer value based on the bytes allocated by the system. Program: #include <stdio.h> #include <conio.h> //function to print the grades of students voidprintdata(intexamdata[][4],int student,int subject); //function to find minimum grade voidmingrade(intexamdata[][4],int student,int subject); //function to find maximum grade voidmaxgrade(intexamdata[][4],int student,int subject); //function to calculate average grade voidgradeavg(intexamdata[][4],int student,int subject); void main() { //array to store the exam data intexamdata[3][4]; int m, n,ch; //array of pointer to function initialization void(processGrades[4])(int[][4],int,int)= { printdata,mingrade,maxgrade,gradeavg }; clrscr(); //input the exam data of each student printf("Enter exam data for the students \n"); for(m =0; m <3; m++) { printf("\nEnter marks for student %d ", m +1); for(n =0; n <4; n++) { printf("\nsubject %d ", n +1); scanf("%d",&examdata[m][n]); } } //print the menu while(1) { clrscr(); printf("\n\n"); printf("Enter a choice: \n"); printf("\n0 Print array of grade"); printf("\n1 Find the minimum grade"); printf("\n2 Find the maximum grade"); printf("\n3 Print the average on all testes for each student"); printf("\n4 End program"); printf("\n?"); scanf("%d",&ch); //check if choiec is invalid if(ch>=0&&ch<=4) { //check to end of program if(ch==4) break; else //otherwise call the function // as choice entered by user (processGrades[ch])(examdata,3,4); } else printf("\n Invalid Choice"); getch(); } } //function definition to print the student exam data voidprintdata(intexamdata[][4],int student,int subject) { int m,n; //print the headers printf("\n\t sub1 sub2 sub3 sub4\n"); //loop to get the data for(m =0; m < student; m++) { //print student number printf("Student %d\t", m +1); for(n =0; n < subject; n++) //print grade of student printf("%d ",examdata[m][n]); printf("\n"); } } //function definition to find minimum grade from the data voidmingrade(intexamdata[][4],int student,int subject) { int low, m,n; //set the highest grade low =100; for(m =0; m < student; m++) for(n =0; n < subject; n++) //check if low value is greater than current grade if(low >examdata[m][n]) //copy the low value low =examdata[m][n]; //print the lowest value printf("\n Minimum Grade is %d ", low); } //function definition to find maximum grade voidmaxgrade(intexamdata[][4],int student,int subject) { int high, m,n; //set the lowest value high =0; for(m =0; m < student; m++) for(n =0; n < subject; n++) //check if current high value is lower than current grade if(high <examdata[m][n]) //copy the higher grade high =examdata[m][n]; //print the highest grade printf("\n Maximum Grade is %d ", high); } //function definition to calculate average grade of each student voidgradeavg(intexamdata[][4],int student,int subject) { inttgrade, m,n; floatavg; for(m =0; m < student; m++) { //set the total grade to 0 tgrade=0; for(n =0; n < subject; n++) //add the grades of current student tgrade+=examdata[m][n]; //calculate the average avg =tgrade/(float)subject; //print the average of current student printf("\nStudent %d average grade is %.2f ", m +1, avg); } } Explanation: In the above code an integer value is input by the user. Then displayBits() function display the bits value of the input integer value. It first checks whether specific system allocates 4 bytes or 2 bytes to store the integer value. It then initializes the bitmask accordingly. A loop executes from 1 to total no of bits for that integer value. In each iteration integer bits are compared with the bitmask using bitwise AND operation to check whether current bit is 1 or 0 and print accordingly. To separate the bits in 8 bits group, after every 8 bit a space is inserted. Sample output:

Solution Summary: The author describes the purpose of the program, which is to display the bits form of an integer value based on the bytes allocated by the system.

MYPROGRAMMINGLAB WITH PEARSON ETEXT

MYPROGRAMMINGLAB WITH PEARSON ETEXT

8th Edition

ISBN: 9780134225340

Author: Deitel

Publisher: PEARSON

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Chapter 7, Problem 7.24E

Chapter 7, Problem 7.26E

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4. |z + 5 - 5i| = 7

14. dz, C: |z❘ C: |z❘ = 0.6 ze² - 2iz H

14. dz, C: |z❘ C: |z❘ = 0.6 ze² - 2iz H

Chapter 7 Solutions

MYPROGRAMMINGLAB WITH PEARSON ETEXT

Ch. 7 - Answer each of the following: The _____ operator...Ch. 7 - Prob. 7.10E Ch. 7 - Do each of the following: Write the function...Ch. 7 - (Simulation: The Tortoise and the Hare) In this...Ch. 7 - (Card Shuffling and Dealing Modification) Modify...Ch. 7 - What does this program do, assuming that the user...Ch. 7 - What does this program do?Ch. 7 - Find the error in each of the following program...Ch. 7 - (Maze Traversal) The following grid is a...Ch. 7 - Prob. 7.23E

Ch. 7 - Prob. 7.24E Ch. 7 - Prob. 7.25E Ch. 7 - What does this program do, assuming that the user...Ch. 7 - (Calculating Circle Circumference, Circle Area or...Ch. 7 - (Calculator Using Function Pointers) Using the...Ch. 7 - (Polling) The Internet and the web are enabling...Ch. 7 - Prob. 7.33MD

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