Chapter 7, Problem 7.24P

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of ${\text{BrO}}_{\text{3}}$ and the number of odd electrons present has to be written.

Concept Introduction:

Free Radical:

A species that contains one or more unpaired electrons is called free radicals.  Because of the unpaired electrons, free radicals are usually very reactive.

Lewis Structure:  A Lewis structure shows a covalent bond as pair of electrons shared between two atoms.

Procedure to write Lewis formulas:

1. 1) The symbols of the atoms that are bonded together in the molecule next to one another are arranged.
2. 2) The total number of valence electrons in the molecule is calculated by adding the number of valence electrons for all the atoms in the molecules.  If the species is an ion, then the charge of ion into account by adding electrons, if it is a negative ion or subtracting electrons if it is a positive ion.
3. 3) A two-electron covalent bond is represented by placing a line between the atoms, which are assumed to be bonded to each other.
4. 4) The remaining valence electrons as lone pairs about each atom are arranged so that the octet rule is satisfied for each other.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of ${\text{SO}}_{\text{3}}$ and the number of odd electrons has to be written.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of $\text{HNO}$ and the number of odd electrons has to be written.

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The Lewis structure of ${\text{HO}}_{\text{2}}$ and the number of odd electrons has to be written.

Concept Introduction:

Refer to part (a).