
Determine how many and which lockers will be open at the end of the student’s activities.

Explanation of Solution
First let us consider for 15 lockers and 15 students.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | |
1 | O | O | O | O | O | O | O | O | O | O | O | O | O | O | O |
2 | O | C | O | C | O | C | O | C | O | C | O | C | O | C | O |
3 | O | C | C | C | O | O | O | C | C | C | O | O | O | C | C |
4 | O | C | C | O | O | O | O | O | C | C | O | C | O | C | C |
5 | O | C | C | O | C | O | O | O | C | O | O | C | O | C | O |
6 | O | C | C | O | C | C | O | O | C | O | O | O | O | C | O |
7 | O | C | C | O | C | C | C | O | C | O | O | O | O | O | O |
8 | O | C | C | O | C | C | C | C | C | O | O | O | O | O | O |
9 | O | C | C | O | C | C | C | C | O | O | O | O | O | O | O |
10 | O | C | C | O | C | C | C | C | O | C | O | O | O | O | O |
11 | O | C | C | O | C | C | C | C | O | C | C | O | O | O | O |
12 | O | C | C | O | C | C | C | C | O | C | C | C | O | O | O |
13 | O | C | C | O | C | C | C | C | O | C | C | C | C | O | O |
14 | O | C | C | O | C | C | C | C | O | C | C | C | C | C | O |
15 | O | C | C | O | C | C | C | C | O | C | C | C | C | C | C |
Let O = Locker Open.
C = Locker Closed.
From the above table, we can make out that there are 3 lockers open at the end of 15th student activity.
For 15 lockers and 15 students, the highest of the perfect squares number is 9 that is 3*3(that is, below number 15, we have 1, 4 (22), and 9 (32) as the perfect square numbers. In that, highest is 9). The square root of the highest of the perfect squares number gives the number of lockers open, that is v9 = 3.
Similarly, for 1000 lockers and students, 961 (31*31=961) is the highest of the perfect squares number. Therefore, v961 = 31, that is 31 lockers are open at the end of 1000th student activity.
So, in an easier way we can say, for a particular student and locker number, the square root of highest of the perfect squares number is the number of lockers that will be open.
All the perfect square numbers (1, 4, 9, 16, 25….till 961) are the lockers that will be open.
Similarly, you can try for the below student and locker numbers:
For, 20 lockers and students, the number of lockers open is 4 (since 16 = 4*4 is the highest of the perfect squares number below 20)
For, 30 lockers and students, the number of lockers open is 5 (since 25 = 5*5 is the highest of the perfect squares number below 30)
Conclusion:
There are 31 lockers open at the end of 1000th student activity. Also, all the perfect square numbers (1, 4, 9, 16, 25.....till 961) are the lockers that will be open.
Want to see more full solutions like this?
Chapter 7 Solutions
Engineering Your Future: Comprehensive
- 2. Figure below shows a U-tube manometer open at both ends and containing a column of liquid mercury of length l and specific weight y. Considering a small displacement x of the manometer meniscus from its equilibrium position (or datum), determine the equivalent spring constant associated with the restoring force. Datum Area, Aarrow_forward1. The consequences of a head-on collision of two automobiles can be studied by considering the impact of the automobile on a barrier, as shown in figure below. Construct a mathematical model (i.e., draw the diagram) by considering the masses of the automobile body, engine, transmission, and suspension and the elasticity of the bumpers, radiator, sheet metal body, driveline, and engine mounts.arrow_forward3.) 15.40 – Collar B moves up at constant velocity vB = 1.5 m/s. Rod AB has length = 1.2 m. The incline is at angle = 25°. Compute an expression for the angular velocity of rod AB, ė and the velocity of end A of the rod (✓✓) as a function of v₂,1,0,0. Then compute numerical answers for ȧ & y_ with 0 = 50°.arrow_forward
- 2.) 15.12 The assembly shown consists of the straight rod ABC which passes through and is welded to the grectangular plate DEFH. The assembly rotates about the axis AC with a constant angular velocity of 9 rad/s. Knowing that the motion when viewed from C is counterclockwise, determine the velocity and acceleration of corner F.arrow_forward500 Q3: The attachment shown in Fig.3 is made of 1040 HR. The static force is 30 kN. Specify the weldment (give the pattern, electrode number, type of weld, length of weld, and leg size). Fig. 3 All dimension in mm 30 kN 100 (10 Marks)arrow_forward(read image) (answer given)arrow_forward
- A cylinder and a disk are used as pulleys, as shown in the figure. Using the data given in the figure, if a body of mass m = 3 kg is released from rest after falling a height h 1.5 m, find: a) The velocity of the body. b) The angular velocity of the disk. c) The number of revolutions the cylinder has made. T₁ F Rd = 0.2 m md = 2 kg T T₂1 Rc = 0.4 m mc = 5 kg ☐ m = 3 kgarrow_forward(read image) (answer given)arrow_forward11-5. Compute all the dimensional changes for the steel bar when subjected to the loads shown. The proportional limit of the steel is 230 MPa. 265 kN 100 mm 600 kN 25 mm thickness X Z 600 kN 450 mm E=207×103 MPa; μ= 0.25 265 kNarrow_forward
- T₁ F Rd = 0.2 m md = 2 kg T₂ Tz1 Rc = 0.4 m mc = 5 kg m = 3 kgarrow_forward2. Find a basis of solutions by the Frobenius method. Try to identify the series as expansions of known functions. (x + 2)²y" + (x + 2)y' - y = 0 ; Hint: Let: z = x+2arrow_forward1. Find a power series solution in powers of x. y" - y' + x²y = 0arrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY





