Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M
and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff:
Ag₂ CO3 = 2 Ag+ caq) + co} (aq)
ksp = 8.10 × 10-12
Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5
a) which salt will precipitate first?
(b)
What % of the first anion precipitated will remain in the solution.
by the time the second anion starts to precipitate?
(c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and
sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate
explanation per answer
Part 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet.
water and benzene. What is the formal concentration of butanoic acid in each phase when
0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene
100 mL of
a) at pit 5.00
b) at pH 9.00
Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/mole
Chapter 7 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 7 - Prob. 7.1VPCh. 7 - Prob. 7.2VPCh. 7 - Prob. 7.3VPCh. 7 - Prob. 7.4VPCh. 7 - Prob. 7.5VPCh. 7 - Prob. 7.6VPCh. 7 - Prob. 7.7QACh. 7 - Prob. 7.8QACh. 7 - Prob. 7.9QACh. 7 - Prob. 7.10QA
Ch. 7 - Prob. 7.11QACh. 7 - Prob. 7.12QACh. 7 - Prob. 7.13QACh. 7 - Prob. 7.14QACh. 7 - Prob. 7.15QACh. 7 - Prob. 7.16QACh. 7 - Prob. 7.17QACh. 7 - Prob. 7.18QACh. 7 - Prob. 7.19QACh. 7 - Prob. 7.20QACh. 7 - Prob. 7.21QACh. 7 - Prob. 7.22QACh. 7 - Prob. 7.23QACh. 7 - Prob. 7.24QACh. 7 - Prob. 7.25QACh. 7 - Prob. 7.26QACh. 7 - Prob. 7.27QACh. 7 - Prob. 7.28QACh. 7 - Prob. 7.29QACh. 7 - Prob. 7.30QACh. 7 - Prob. 7.31QACh. 7 - Prob. 7.32QACh. 7 - Prob. 7.33QACh. 7 - Prob. 7.35QACh. 7 - Prob. 7.36QACh. 7 - Prob. 7.37QACh. 7 - Prob. 7.38QACh. 7 - Prob. 7.39QACh. 7 - Prob. 7.40QACh. 7 - Prob. 7.41QACh. 7 - Prob. 7.42QACh. 7 - Prob. 7.43QACh. 7 - Prob. 7.44QACh. 7 - Prob. 7.45QACh. 7 - Prob. 7.46QACh. 7 - Prob. 7.47QACh. 7 - Prob. 7.48QACh. 7 - Prob. 7.49QACh. 7 - Prob. 7.50QACh. 7 - Prob. 7.51QACh. 7 - Prob. 7.52QACh. 7 - Prob. 7.53QACh. 7 - Prob. 7.54QACh. 7 - Prob. 7.55QACh. 7 - Prob. 7.56QACh. 7 - Prob. 7.57QACh. 7 - Prob. 7.58QACh. 7 - Prob. 7.59QACh. 7 - Prob. 7.60QACh. 7 - Prob. 7.61QACh. 7 - Prob. 7.62QACh. 7 - Prob. 7.63QACh. 7 - Prob. 7.64QACh. 7 - Prob. 7.65QACh. 7 - Prob. 7.66QACh. 7 - Prob. 7.67QACh. 7 - Prob. 7.68QACh. 7 - Prob. 7.69QACh. 7 - Prob. 7.70QACh. 7 - Prob. 7.71QACh. 7 - Prob. 7.72QACh. 7 - Prob. 7.73QACh. 7 - Prob. 7.74QACh. 7 - Prob. 7.75QACh. 7 - Prob. 7.76QACh. 7 - Prob. 7.77QACh. 7 - Prob. 7.78QACh. 7 - Prob. 7.79QACh. 7 - Prob. 7.80QACh. 7 - Prob. 7.81QACh. 7 - Prob. 7.82QACh. 7 - Prob. 7.83QACh. 7 - Prob. 7.84QACh. 7 - Prob. 7.85QACh. 7 - Prob. 7.86QACh. 7 - Prob. 7.87QACh. 7 - Prob. 7.88QACh. 7 - Prob. 7.89QACh. 7 - Prob. 7.90QACh. 7 - Prob. 7.91QACh. 7 - Prob. 7.92QACh. 7 - Prob. 7.93QACh. 7 - Prob. 7.94QACh. 7 - Prob. 7.95QACh. 7 - Prob. 7.96QACh. 7 - Prob. 7.97QACh. 7 - Prob. 7.98QACh. 7 - Prob. 7.99QACh. 7 - Prob. 7.100QACh. 7 - Prob. 7.101QACh. 7 - Prob. 7.102QACh. 7 - Prob. 7.103QACh. 7 - Prob. 7.104QACh. 7 - Prob. 7.105QACh. 7 - Prob. 7.106QACh. 7 - Prob. 7.107QACh. 7 - Prob. 7.108QACh. 7 - Prob. 7.109QACh. 7 - Prob. 7.110QA
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- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Rank the compounds in each group below according to their reactivity toward electrophilic aromatic substitution (most reactive = 1; least reactive = 3). Place the number corresponding to the compounds' relative reactivity in the blank below the compound. a. CH₂F CH3 F b. At what position, and on what ring, is bromination of phenyl benzoate expected to occur? Explain your answer. :0: C-O phenyl benzoate 6.Consider the reaction below to answer the following questions. A B C NO₂ FeBr3 + Br₂ D a. The nucleophile in the reaction is: BODADES b. The Lewis acid catalyst in the reaction is: C. This reaction proceeds d. Draw the structure of product D. (faster or slower) than benzene.arrow_forwardPart 2. A solution of 6.00g of substance B in 100.0mL of aqueous solution is in equilibrium, at room temperature, wl a solution of B in diethyl ether (ethoxyethane) containing 25.0 g of B in 50.0 mL 9) what is the distribution coefficient of substance B b) what is the mass of B extracted by shaking 200 ml of an aqueous solution containing 10g of B with call at room temp): i) 100 mL of diethyl ether ii) 50ml of diethyl ether twice iii) 25ml of diethyl ether four timesarrow_forward- Rank the following groups of compounds from most acidic (1) to least acidic (4). Place the number corresponding to the compound's relative rank in the blank below the structure. a. NO₂ NO₂ CH2CH2CH2CH2OH CH3 CH3CH2CHOH CH3CH2CH2CH2OH NO₂ CH3CHCH2CH2OH b. OH OH CH₂OH CO₂H HC CN CN CNarrow_forward
- Give the major organic product(s) of the following reactions or sequences of reactions. Show all relevant stereochemistry a. H MgBr 1. ether 2. H₂O* 4 COH b. 1. LIAIH, ether 2. H₂O Choose the best reagent(s) for carrying out the following conversions from the list provided below. Place the letter of the best choice in the blank to the left of the conversion. Reagents may be used more than once. a. 1. CH3MgBr, ether 2. H3O+ NaOH b. 1. PBr3 2. C. 2. 1. (CH3)3SiCl, (CH3CH2)3N CH3MgBr, ether 3. H₂O*+ 2. H3O+ e. 1. p-TosCl, pyridine f. نها g. 2. NaOH CrO3, H₂SO4, H₂O 1. NaBH4, ethanol 2. H30* h. PCC, CH2Cl2 Ovoldo-6 a. b. OH OH H OH O any organicarrow_forwardDetermine the rate law for sodium thiosulfate from the following data: [Na2S2O3] Time (s) 0.0318 230. 0.0636 57.5arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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