Because of Earth’s rotation about its axis, a point onthe equator has a centripetal acceleration of 0.034 0 m/s2,whereas a point at the poles has no centripetal acceleration.(a) Show that, at the equator, the gravitational force on anobject (the object’s true weight) must exceed the object’sapparent weight. (b) What are the apparent weights of a75.0-kg person at the equator and at the poles? (Assume Earthis a uniform sphere and take g = 9.800 m/s2.)
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
Because of Earth’s rotation about its axis, a point on
the equator has a centripetal acceleration of 0.034 0 m/s2,
whereas a point at the poles has no centripetal acceleration.
(a) Show that, at the equator, the gravitational force on an
object (the object’s true weight) must exceed the object’s
apparent weight. (b) What are the apparent weights of a
75.0-kg person at the equator and at the poles? (Assume Earth
is a uniform sphere and take g = 9.800 m/s2.)
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