The balanced chemical equations for the two described reactions are to be written. Concept Introduction: Chemical equations having an equal number of atoms of each type on both sides are known as a balanced chemical equation. For balancing a chemical equation, reactants and products are multiplied by coefficients. The steps to balance chemical equation are: If there is an element that occurs in only one compound on both sides of the equation, balance it first. If there are more than one such element is there, balance metals before non-metals. If the element is present in a free state on both the sides of the equation, balance it last. These elements are balanced by adjusting the coefficients. If coefficients are present in a fraction, convert it into whole numbers by multiplying with the appropriate number.
The balanced chemical equations for the two described reactions are to be written. Concept Introduction: Chemical equations having an equal number of atoms of each type on both sides are known as a balanced chemical equation. For balancing a chemical equation, reactants and products are multiplied by coefficients. The steps to balance chemical equation are: If there is an element that occurs in only one compound on both sides of the equation, balance it first. If there are more than one such element is there, balance metals before non-metals. If the element is present in a free state on both the sides of the equation, balance it last. These elements are balanced by adjusting the coefficients. If coefficients are present in a fraction, convert it into whole numbers by multiplying with the appropriate number.
Solution Summary: The author explains how to write a balanced chemical equation for the formation of oleum by reaction of sulfur trioxide with sulfuric acid
The balanced chemical equations for the two described reactions are to be written.
Concept Introduction:
Chemical equations having an equal number of atoms of each type on both sides are known as a balanced chemical equation.
For balancing a chemical equation, reactants and products are multiplied by coefficients.
The steps to balance chemical equation are:
If there is an element that occurs in only one compound on both sides of the equation, balance it first.
If there are more than one such element is there, balance metals before non-metals.
If the element is present in a free state on both the sides of the equation, balance it last. These elements are balanced by adjusting the coefficients.
If coefficients are present in a fraction, convert it into whole numbers by multiplying with the appropriate number.
b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not
themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting
four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation
you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be
both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the
four structures.
Compound C
Possible conformations (circle one):
Дет
Lab Data
The distance entered is out of the expected range.
Check your calculations and conversion factors.
Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3?
Did you report your data to the correct number of significant figures?
- X
Experimental Set-up
HCI-NH3
NH3-HCI
Longer Tube
Time elapsed (min)
5 (exact)
5 (exact)
Distance between cotton balls (cm)
24.30
24.40
Distance to cloud (cm)
9.70
14.16
Distance traveled by HCI (cm)
9.70
9.80
Distance traveled by NH3 (cm)
14.60
14.50
Diffusion rate of HCI (cm/hr)
116
118
Diffusion rate of NH3 (cm/hr)
175.2
175.2
How to measure distance and calculate rate
For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically:
1:1 (one mole of EDTA per mole of metal ion)
2:1 (two moles of EDTA per mole of metal ion)
1:2 (one mole of EDTA per two moles of metal ion)
None of the above
Chapter 7 Solutions
Introductory Chemistry, Books a la Carte Edition & Modified MasteringChemistry with Pearson eText -- ValuePack Access Card -- for Introductory Chemistry Package
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