Bundle: Sustainable Energy, 2nd + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
2nd Edition
ISBN: 9781337896535
Author: Richard A. Dunlap
Publisher: Cengage Learning
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Chapter 7, Problem 3P
To determine
Show the energy released from equation 7.7 as
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A small particle has charge -4.30 μC and mass 2.00×10-4 kg. It moves from point A,
where the electric potential is VA = 260 V, to point B, where the electric potential
VB = 960 V is greater than the potential at point A. The electric force is the only
force acting on the particle. The particle has a speed of 4.60 m/s at point A.
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Solution of Electric force and electric potential.
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Part A
What is its speed at point B?
Express your answer in meters per second.
ΜΕ ΑΣΦ
v =
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Part B
Is it moving faster or slower at B than at A?
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Slower
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m/s
Two particles each have a mass of 6.1 x 10-2 kg. One has a charge of +5.0 x 106 C, and the other has a charge of -5.0 x 10-6 C. They are
initially held at rest at a distance of 1.1 m apart. Both are then released and accelerate toward each other. How fast is each particle
moving when the separation between them is one-third its initial value?
Number i
Units
B
91
91
92
92
A
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Bundle: Sustainable Energy, 2nd + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
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