Find the second moment of area of a 4 in diameter about the x - x and y - y axes.

Question

Compute for the stresses (initial, const and final stage) and check for compliance in NSCP provisions. Also compute the following: 1. Compute and check if the section is Uncracked, Transition or Cracked as per NSCP. 2. Compute for its flexural capacity and check if it could carry the given load. BEAM SECTION NOT TO SCALE 1400mm 300 $1098 400 */ 400*300* 300 200 300 100 ORIGINAL SECTION/PRECA CAST-IN-PLACE (CIP) PART PRECAST LOADING AT SERVICE M • 21 KN (DEAD LOAD ONLY) 21KN 4.75m 9.25m CIVEN DATA STRANDS: 12-02 AT 120KN/STRAND (GOMM FROM BOTTOM) 8-2 AT 120HN/STRAND (120mm FROM BOTTOM) fc 42.5 MPa (BEAM) fc 38 MPa (CIP) f'a = 80% or fa fp-1860 MPa ESTRANDS 1976Pa OONG 23.6/m³ LOES 1-8% Loss 18% APPLY 3M LIVE LOAD AT CONST. PHASE

Answer 1

Question

Chapter 7, Problem 37P

To determine

Find the second moment of area of a 4 in diameter about the x-x and y-y axes.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Compute for the stresses (initial, const and final stage) and check for compliance in NSCP provisions. Also compute the following: 1. Compute and check if the section is Uncracked, Transition or Cracked as per NSCP. 2. Compute for its flexural capacity and check if it could carry the given load. BEAM SECTION NOT TO SCALE 1400mm 300 $1098 400 */ 400*300* 300 200 300 100 ORIGINAL SECTION/PRECA CAST-IN-PLACE (CIP) PART PRECAST LOADING AT SERVICE M • 21 KN (DEAD LOAD ONLY) 21KN 4.75m 9.25m CIVEN DATA STRANDS: 12-02 AT 120KN/STRAND (GOMM FROM BOTTOM) 8-2 AT 120HN/STRAND (120mm FROM BOTTOM) fc 42.5 MPa (BEAM) fc 38 MPa (CIP) f'a = 80% or fa fp-1860 MPa ESTRANDS 1976Pa OONG 23.6/m³ LOES 1-8% Loss 18% APPLY 3M LIVE LOAD AT CONST. PHASE

Please explain all your steps. Thank you.

10000 Quizl:Design a grit chamber for a horizontal velocity 250 mm/s, minimum flow 5,000 m³/day, maximum 20,000 m³/day, average flow is 12,500m³/day, S.O.R= 0.017 m/s, For a parabolic channels A =2/3 WD, detention time = 1 min Q Ac == HxW vs for inorganic particles = SOR As = LxW As V=Qxt=LxWxH Z=CxW2 Q (m³/day) | Ac (m²) W (m) | Z (m)