Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Expert Solution & Answer
Chapter 7, Problem 36E
Explanation of Solution
BCNF (Boyce Codd Normal Form):
A relation is said to be in BCNF if it holds the following 2 conditions:
- The relation is in Third Normal Form
- For every dependency X→a, X is superkey.
Every binary relation which means every schema consisting of exactly 2 attributes is said to be in BCNF.
In order to prove that, consider all possible combinations of functional dependencies on a relation R with 2 attributes A1 and A2.
Case1: A1→A2
In this case, A1 is the candidate key and hence also a superkey as candidate keys is minimal superkeys.
So, the BCNF condition satisfies in this case...
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I need help to resolve the case, thank you
In 32-bit MSAM, You were given the following negative array. write a program that converts each array element to its positive representation. Then add all these array elements and assign them to the dl register. .data myarr sbyte -5, -6, -7, -4.code ; Write the rest of the program and paste the fully working code in the space below.
the dl register should have the value 22 after summing up all elements in the array.
Microprocessor 8085 Lab Experiment
Experiment No. 3 Logical Instructions
Write programs with effects
1. B=(2Dh XOR D/2) - (E AND 2Eh+1) when E=53, D=1Dh
2. HL= (BC+HL) XOR DE (use register pair when necessary), when BC=247,
HL 516, DE 12Ach
3. Reset bits 1,4,6 of A and set bits 3,5 when A=03BH
Write all as table (address line.hexacode,opcede,operant.comment with flags)
Chapter 7 Solutions
Database System Concepts
Ch. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Explain how functional dependencies can be used to...Ch. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Prob. 6PECh. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - Prob. 9PECh. 7 - Prob. 10PE
Ch. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 13PECh. 7 - Prob. 14PECh. 7 - Prob. 15PECh. 7 - Prob. 16PECh. 7 - Prob. 17PECh. 7 - Prob. 18PECh. 7 - Prob. 19PECh. 7 - Prob. 20PECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 -
Explain what is meant by repetition of...Ch. 7 -
Why are certain functional dependencies called...Ch. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43E
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